Compare your submission with the following document and, if necessary, self-critique your work.

In order to self-critique, submit a copy of your original submission, inserting revisions and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).

 

Note that the quality of this video was intentionally limited. 

The questions posed on the Seed Question were as follows, with commentary in bold:

• How accurately do you think you can measure the time between two events using the TIMER program?

 

Your answer to this question should have consisted of a decimal number representing the number of seconds of uncertainty your timing using the program, and you should explain why you believe this number to be a reasonable estimate of the uncertainty.


• What is the shortest time interval you think you would be able to measure with reasonable accuracy? </p>
 

Your answer to this question should have been a decimal number representing the shortest time interval you believe could be timed accurately. 

Your answer should be accompanied by an explanation of why you believe it to be reasonable.

Note that the time interval specified in your answer to the present question should be shorter than the time you specified in the first question.  You can't reasonably time an interval that is shorter than your uncertainty in timing.


• How does the percent error in timing intervals change as the time between the events gets smaller? </p>
 

You should look through the recommended calculations at the end of this document and consider whether your answer to this question is consistent with the pattern that emerges from those questions.

STUDENT SOLUTION

I did this by if my intervals change by .2 per every second .2/1.0s = 20% error if the time is lessoned between
intervals .1/1.0s = 10% error..

so the error is decreasing, I juse want top make sure I am corret in thinking here???????????

INSTRUCTOR RESPONSE

You're on the right track and you're doing some very good thinking.

However the size of the uncertainty doesn't generally decrease as intervals get shorter.

For example your neurological response does not get better with shorter intervals. So you can't expect the uncertaintly associated with that response to decrease.


• How accurately are you able to measure the positions of the ball and the pendulum in the initial video?

Your answers here should include numerical estimates of your uncertainties and an explanation of how your estimates are based on what you saw on the video.  If they weren't, consider the following questions:


 

Recommended calculations:

Answers to many of the following calculations are given at the end of the page.

Answer the following questions about percents:

Suppose you a single cycle of a four pendulums.  Assume that your timing is accurate to within +- .1 second.  Another way of saying the same thing is to say that the uncertainty in the timing is +- .1 second.

What happens to the percent uncertainty as the time required for a cycle decreases?  Can you explain why this is the case?

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Answers to some of the calculations:

2 percent of 50 is .02 * 50 = 1

.5 percent of 20 is .005 * 20 = .1

If we divide 2 by 50 we get 2 / 50 = .04, which is 4%.  So 2 is 4% of 50.

If we divide 2 by 10 we get 2 / 10 = .2, which is 20%.  So 2 is 20% of 10.

.2 percent of a number is .002 multiplied by the number.  Call the number x.  If .2 percent x is 50, then .002 * x = 50 and x = 50 / .002 = 25 000.

5 percent of an unknown number x is .05 * x.  If 5 percent of this number is 20, the .05 * x = 20 and x = 20 / .05 = 400.

If we divide .1 sec by 5 sec we get .1 sec / (5 sec) = .02, so .1 sec is 2 % of 5 sec.

If we divide .1 sec by 2 sec we get .1 sec / (2 sec) = .05, so .1 sec is 5 % of 2 sec.

If we divide .1 sec by .5 sec we get .1 sec / (.5 sec) = .2, so .1 sec is 20 % of .05 sec.