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(Note: If you are having trouble with this exercise, see Exercises for the Perplexed at the end of this document).

For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each. 

Here you know v0, vf and `ds, with respective values 10 cm/s, 20 cm/s and 45 cm.

  • From v0 and vf, since accel is uniform you can easily find vAve.

  • Then you can use the definition of vAve along with the value of `ds to obtain `dt.

  • Finally you can determine `dv from v0 and vf and use the definition of acceleration, along with `dt, to find a.

Here you know a, `dt and vf, with respective values 10 cm/s^2, 3 sec and 50 cm/s.

  • From a and `dt you can find `dv.

  • From vf and `dv you can find v0.

  • From v0 and vf you can find vAve, which with `dt allows you to find `ds.

Here you know v0, a and `ds, with respective values 0 (i.e., starting from rest), 20 cm/s^2 and 30 cm.

You can't directly reason out anything from these quantities:

  • To use the definition of vAve you would need to know either vf (to be used with v0) or `dt (to be used with `ds).

  • To use the definition of aAve you would have to know either vf (to be used with v0 to find `dv, so that you have a and `dv) or `dt (with a and `dt you can find `dv, then from v0 can find vf).

You can use the third or fourth equation of motion so get a result.

  • However the intuitive meaning of the third equation (`ds= v0 `dt + 1/2 a `dt^2) and the fourth (vf^2 = v0^2 + 2 a `ds) are not intuitively clear and directly related to the definitions of velocity and acceleration.

  • So while you would get a good solution, it would not have been obtained using direct reasoning in terms of the definition.  There's nothing wrong with the solution, it just isn't directly reasoned.

Then for each situation answer the following:

In the first situation you can directly determine vAve from the given quantities v0 and vf.

In the second situation you can't determine vAve directly from the given information, but in a couple of steps you can directly reason out all the quantities. 

In the third situation you can't get anywhere with direct reasoning, so you have to use the third and/or fourth equations of motion.

Is it possible to directly determine `dv? 

In the first situation you can directly determine `dv from the given quantities v0 and vf.

In the second situation you can directly determine `dv from a and `dt.

In the third situation you can't get anywhere with direct reasoning, so you have to use the third and/or fourth equations of motion.

 

Exercises for the Perplexed

If you are having trouble with this problem and think it would be helpful, you are welcome to submit this part of the document: 

There are a number of questions here, but the answers are short so this won't necessarily take you very long. If it takes you more than 30 minutes, submit what you have so I can respond with help and suggestions. Use both the form and email. Simply submit a copy of the entire document, with your answers to these questions (and/or questions you might have) inserted in the appropriate places:

 

What are some possible units of position?
answer:
What does `ds stand for?
What therefore are some possible units of `ds?
answer:
What is the definition of velocity?
What therefore are some possible units of velocity?
answer:
What is the definition of acceleration?
What therefore are some possible units of acceleration?
answer:
Does `ds stand for change in position, change in velocity, change in clock time or change in acceleration?
Which quantities in your submission here identify `ds as a quantity which doesn't have the units of `ds?
answer:
Does `dts stand for change in position, change in velocity, change in clock time or change in acceleration?
Which quantities in your submission here identify `dt as a quantity which doesn't have the units of `dt?
answer:
Does v0 stand for a position, a velocity, a clock time or an acceleration?
Which quantities in your submission here identify v0 as a quantity which doesn't have the units of v0?
answer:
Does vf stand for a position, a velocity, a clock time or an acceleration?
Which quantities in your submission here identify vf as a quantity which doesn't have the units of vf?
answer:
Does a stand for a position, a velocity, a clock time oran acceleration?
Which quantities in your submission here identify a as a quantity which doesn't have the units of a?