Additional Notes:
A student gives the following data; the data look very reasonable:
Rubber band length, the number of dominoes supported at this length, the mean
and the
standard deviation of the sliding distance in cm, and the energy associated with
the stretch, for each
set of 5 trials:
0,0 , 8cm 3 dominos </p>
.61,.0746 8.4cm 4 dominos </p>
.97,.09747 8.7cm 6 dominos </p>
1.17,.1204 8.9cm 8 dominos </p>
1.3,.03536 9.2cm 1o dominos </p>
The student asks the following question:
I need you to explain to me how to get the Joules cause Im sure I didnt do it
right so If you could
explain it I would appreciate it </p>
INSTRUCTOR RESPONSE:
Each domino supported requires an additional tension force of .2 Newtons.
When force is exerted in the direction of motion, as in the case of the rubber
band propelling the domino block, the work done by the force is
The average force exerted between the 8 domino length (where force is
about 8 dominoes * .2 N / domino = 1.6 N) and the 10 domino length (where force
is about 2.0 N) is very close to 1.8 N, the average of the minimum and maximum
forces exerted on that interval.
The distance through which this force acts is the difference between the 8
domino length and the 10 domino length.
The standard unit of work in the Joule, which is a Newton * meter. So if your
average force is expressed in Newtons and your distance in meters, the work will
be in Joules.
The fundamental unit of a Newton is a kg * m / s^2; the fundamental unit of a
Joule is a kg m^2 / s^2.
See also links to solutions/discussion of related cq problems, which have
addressed this type of situation, and the preceding experiment on force vs.
displacement.
For your data it appears that the rubber band contracts .3 cm between the 8 and
10 domino lengths, so that the work done in this contraction would be .3 cm *
1.8 N = .003 m * 1.8 N = .054 Joule.
Similar calculations could be made for the intervals between 6 and 8 dominoes,
between 4 and 6 dominoes, etc..
If the rubber band contracts from the 10 domino length to its original length,
the total work would be obtained by adding up the work for each intervening
interval.