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Areas |
reviews the meaning, reasoning and calculation of areas of some common geometric figures | the meaning of areas, reasoning about areas, some important formulas for areas |
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If your solution to stated problem does not match the given solution, you should self-critique per instructions at
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Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.
qa areas etc
001. Areas
Question:
`q001. There are 11
questions and 7 summary questions in this assignment.
What is the area of a rectangle whose dimensions are 4 m by
3 meters.
Your solution:
Confidence Assessment:
Given Solution:
`aA 4 m by 3 m rectangle can be divided into 3 rows of 4
squares, each 1 meter on a side. This
makes 3 * 4 = 12 such squares. Each 1
meter square has an area of 1 square meter, or 1 m^2. The total area of the rectangle is therefore
12 square meters, or 12 m^2.
The formula for the area of a rectangle is A = L * W, where
L is the length and W the width of the rectangle. Applying this formula to the present problem
we obtain area A = L * W = 4 m * 3 m = (4 * 3) ( m * m
) = 12 m^2.
Note the use of the unit m, standing for meters, in the
entire calculation. Note that m * m =
m^2.
FREQUENT STUDENT ERRORS
The following are the most common erroneous responses to this question:
4 * 3 = 12
4 * 3 = 12 meters
INSTRUCTOR EXPLANATION OF ERRORS
Both of these solutions do indicate that we multiply 4 by 3, as is appropriate.
However consider the following:
4 * 3 = 12.
4 * 3 does not equal 12 meters.
4 * 3 meters would equal 12 meters, as would 4 meters * 3.
However the correct result is 4 meters * 3 meters, which is not 12 meters but 12 meters^2, as shown in the given solution.
To get the area you multiply the quantities 4 meters and 3 meters, not the numbers 4 and 3. And the result is 12 meters^2, not 12 meters, and not just the number 12.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q002. What is the area
of a right triangle whose legs are 4.0 meters and 3.0 meters?
Your solution:
Confidence Assessment:
Given Solution:
`aA right triangle can be joined along its hypotenuse with
another identical right triangle to form a rectangle. In this case the rectangle would have
dimensions 4.0 meters by 3.0 meters, and would be divided by any diagonal into
two identical right triangles with legs of 4.0 meters and 3.0 meters.
The rectangle will have area A = L * W = 4.0 m * 3.0 m = 12
m^2, as explained in the preceding problem.
Each of the two right triangles, since they are identical, will
therefore have half this area, or 1/2 * 12 m^2 = 6.0 m^2.
The formula for the area of a right triangle with base b and altitude h is A = 1/2 * b * h.
STUDENT QUESTION
Looking at your solution I think I am a bit rusty on finding
the area of triangles. Could you give me a little more details
on how you got your answer?
INSTRUCTOR RESPONSE
As explained, a right triangle is half of a rectangle.
There are two ways to put two right triangles together,
joining them along the hypotenuse. One of these ways gives you a rectangle. The
common hypotenuse thus forms a diagonal line across the rectangle.
The area of either triangle is half the area of this rectangle.
If this isn't clear, take a blade or a pair of scissors and cut a rectangle out of a piece of paper. Make sure the length of the rectangle is clearly greater than its width. Then cut your rectangle along a diagonal, to form two right triangles.
Now join the triangles together along the hypotenuse. They will either form a rectangle or they won't. Either way, flip one of your triangles over and again join them along the hypotenuse. You will have joined the triangles along a common hypotenuse, in two different ways. If you got a rectangle the first time, you won't have one now. And if you have a rectangle now, you didn't have one the first time.
It should be clear that the two triangles have equal areas
(allowing for a little difference because we can't really cut them with complete
accuracy).
Self-critique (if necessary):
Self-critique Rating:
Question:
`q003. What is the area
of a parallelogram whose base is 5.0 meters and whose altitude is 2.0 meters?
Your solution:
Confidence Assessment:
Given Solution:
`aA parallelogram is easily rearranged into a rectangle by
'cutting off' the protruding end, turning that portion upside down and joining
it to the other end. Hopefully you are
familiar with this construction. In any
case the resulting rectangle has sides equal to the base and the altitude so
its area is A = b * h.
The present rectangle has area A = 5.0 m * 2.0 m = 10 m^2.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q004. What is the area
of a triangle whose base is 5.0 cm and whose altitude is 2.0 cm?
Your solution:
Confidence Assessment:
Given Solution:
`aIt is possible to join any triangle with an identical copy
of itself to construct a parallelogram whose base and altitude are equal to the
base and altitude of the triangle. The
area of the parallelogram is A = b * h, so the area of each of the two identical
triangles formed by 'cutting' the parallelogram about the approriate diagonal
is A = 1/2 * b * h. The area of the
present triangle is therefore A = 1/2 * 5.0 cm * 2.0 cm = 1/2 * 10 cm^2 = 5.0
cm^2.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q005. What is the area
of a trapezoid with a width of 4.0 km and average altitude of 5.0 km?
Your solution:
Confidence Assessment:
Given Solution:
`aAny trapezoid can be reconstructed to form a rectangle
whose width is equal to that of the trapezoid and whose altitude is equal to
the average of the two altitudes of the trapezoid. The area of the rectangle, and therefore the
trapezoid, is therefore A = base * average altitude. In the present case this area is A = 4.0 km *
5.0 km = 20 km^2.
STUDENT SOLUTION ILLUSTRATING NEED TO USE UNITS IN ALL STEPS
A=Base time average altitude therefore………A=4 *5= 20 km ^2
INSTRUCTOR COMMENT
A = (4 km) * (5 km) = 20 km^2.
Use the units at every step. km * km = km^2, and this is why the answer comes
out in km^2.
Try to show the units and how they work out in every step of the solution.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q006. What is the area
of a trapezoid whose width is 4 cm in whose altitudes are 3.0 cm and 8.0 cm?
Your solution:
Confidence Assessment:
Given Solution:
`aThe area is equal to the product of the width and the
average altitude. Average altitude is (3
cm + 8 cm) / 2 = 5.5 cm so the area of the trapezoid is A = 4 cm * 5.5 cm = 22
cm^2.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q007. What is the area
of a circle whose radius is 3.00 cm?
Your solution:
Confidence Assessment:
Given Solution:
`aThe area of a circle is A = pi * r^2, where r is the
radius. Thus
A = pi * (3 cm)^2 = 9 pi cm^2.
Note that the units are cm^2, since the cm unit is part r,
which is squared.
The expression 9 pi cm^2 is exact. Any decimal equivalent is an approximation. Using the 3-significant-figure approximation
pi = 3.14 we find that the approximate area is A = 9 pi cm^2 = 9 * 3.14 cm^2 =
28.26 cm^2, which we round to 28.3 cm^2 to match the number of significant
figures in the given radius.
Be careful not to confuse the formula A = pi r^2, which
gives area in square units, with the formula C = 2 pi r for the
circumference. The latter gives a result
which is in units of radius, rather than square units. Area is measured in square units; if you get
an answer which is not in square units this tips you off to the fact that
you've made an error somewhere.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q008. What is the
circumference of a circle whose radius is exactly 3 cm?
Your solution:
Confidence Assessment:
Given Solution:
`aThe circumference of this circle is
C = 2 pi r = 2 pi * 3 cm = 6 pi cm.
This is the exact area.
An approximation to 3 significant figures is 6 * 3.14 cm = 18.8 cm.
Note that circumference is measured in the same units as
radius, in this case cm, and not in cm^2.
If your calculation gives you cm^2 then you know you've done something
wrong.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q009. What is the area
of a circle whose diameter is exactly 12 meters?
Your solution:
Confidence Assessment:
Given Solution:
`aThe area of a circle is A = pi r^2, where r is the
radius. The radius of this circle is
half the 12 m diameter, or 6 m. So the
area is
A = pi ( 6 m )^2 = 36 pi m^2.
This result can be approximated to any desired accuracy by
using a sufficient number of significant figures in our approximation of
pi. For example using the
5-significant-figure approximation pi = 3.1416 we obtain A = 36 m^2 * 3.1416 =
113.09 m^2.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q010. What is the area
of a circle whose circumference is 14 `pi meters?
Your solution:
Confidence Assessment:
Given Solution:
`aWe know that A = pi r^2.
We can find the area if we know the radius r. We therefore attempt to use the given
information to find r.
We know that circumference and radius are related by C = 2
pi r. Solving for r we obtain r = C / (2
pi). In this case we find that
r = 14 pi m / (2 pi) = (14/2) * (pi/pi) m = 7 * 1 m = 7 m.
We use this to find the area
A = pi * (7 m)^2 = 49 pi m^2.
STUDENT QUESTION:
Is the answer not 153.86 because you have multiply 49 and
pi????
INSTRUCTOR RESPONSE
49 pi is exact and easier to connect to radius 7 (i.e., 49 is clearly the square of 7) than the number 153.86 (you can't look at that number and see any connection at all to 7).
You can't express the exact result with a decimal. If the radius is considered exact, then only 49 pi is an acceptable solution.
If the radius is considered to be approximate to some degree,
then it's perfectly valid to express the result in decimal form, to an
appropriate number of significant figures.
153.86 is a fairly accurate approximation.
However it's not as accurate as it might seem, since you used only 3 significant figures in your approximation of pi (you used 3.14). The first three figures in your answer are therefore significant (though you need to round); the .86 in your answer is pretty much meaningless.
If you round the result to 154 then the figures in your answer are significant and meaningful.
Note that a more accurate approximation (though still just an approximation) to 49 pi is 153.93804. An approximation to 5 significant figures is 153.94, not 153.86.</h3>
Self-critique (if necessary):
Self-critique Rating:
Question:
`q011. What is the
radius of circle whose area is 78 square meters?
Your solution:
Confidence Assessment:
Given Solution:
`aKnowing that A = pi r^2 we solve for r. We first divide both sides by pi to obtain A
/ pi = r^2. We then reverse the sides
and take the square root of both sides, obtaining r = sqrt(
A / pi ).
Note that strictly speaking the solution to r^2 = A / pi is
r = +-sqrt( A / pi ), meaning + sqrt( A / pi) or -
sqrt(A / pi). However knowing that r
and A are both positive quantities, we can reject the
negative solution.
Now we substitute A = 78 m^2 to obtain
r = sqrt( 78 m^2 / pi) = sqrt(78 /
pi) m.{}
Approximating this quantity to 2 significant figures we
obtain r = 5.0 m.
STUDENT QUESTION
Why after all the squaring and dividing is the final product
just meters and not meters squared????
INSTRUCTOR RESPONSE
It's just the algebra of the units.
sqrt( 78 m^2 / pi) = sqrt(78) * sqrt(m^2) / sqrt(pi). The sqrt(78) / sqrt(pi)
comes out about 5.
The sqrt(m^2) comes out m.
This is a good thing, since radius is measured in meters and not square meters.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q012. Summary Question
1: How do we visualize the area of a
rectangle?
Your solution:
Confidence Assessment:
Given Solution:
`aWe visualize the rectangle being
covered by rows of 1-unit squares. We
multiply the number of squares in a row by the number of rows. So the area is A = L * W.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q013. Summary Question
2: How do we visualize the area of a
right triangle?
Your solution:
Confidence Assessment:
Given Solution:
`aWe visualize two identical right
triangles being joined along their common hypotenuse to form a rectangle whose
length is equal to the base of the triangle and whose width is equal to the
altitude of the triangle. The area of the
rectangle is b * h, so the area of each triangle is 1/2 * b * h.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q014. Summary Question
3: How do we calculate the area of a
parallelogram?
Your solution:
Confidence Assessment:
Given Solution:
`aThe area of a parallelogram is equal to the product of its
base and its altitude. The altitude is
measured perpendicular to the base.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q015. Summary Question
4: How do we calculate the area of a
trapezoid?
Your solution:
Confidence Assessment:
Given Solution:
`aWe think of the trapezoid being
oriented so that its two parallel sides are vertical, and we multiply the
average altitude by the width.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q016. Summary Question
5: How do we calculate the area of a
circle?
Your solution:
Confidence Assessment:
Given Solution:
`aWe use the formula A = pi r^2, where r is the radius of
the circle.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q017. Summary Question
6: How do we calculate the circumference
of a circle? How can we easily avoid
confusing this formula with that for the area of the circle?
Your solution:
Confidence Assessment:
Given Solution:
`aWe use the formula C = 2 pi r. The formula for the area involves r^2, which
will give us squared units of the radius.
Circumference is not measured in squared units.
Self-critique (if necessary):
Self-critique Rating:
Question:
`q018. Explain how you
have organized your knowledge of the principles illustrated by the exercises in
this assignment.
Self-critique (if necessary):
Self-critique Rating: