Having defined acceleration, we attempt to establish at least one set of conditions under which acceleration should be uniform, namely a car coasting down a constant incline. We take data for later analysis.
We then formulate the consequences of uniform acceleration, using
We finally see that from uniform acceleration and time interval, we can determine change in velocity while from uniform acceleration and distance we determine the change in the squared velocity.
The following questions arise:
We begin with an experiment to test whether on an inclined plane with a constant slope, the acceleration seems to be constant regardless of velocity or position on the slope.
Video clip #01
We begin with the return to the situation in which we know `ds, a and v0. Recall that the two most fundamental equations of motion are
vf = v0 + a `dt,
which was derived by considering what could be concluded from knowledge of v0, a and `dt, and which indicates the by-now obvious fact that when we add the change in velocity `dv = a `dt to the initial velocity we get the final velocity, and
`ds = (vf + v0) / 2 * `dt,
derived from the initially known quantities v0, vf and `dt, which indicates that to get the displacement we multiply the average velocity by the time interval.
Would have also seen that knowing v0, a and `dt, are natural line of reasoning leads to the third fundamental equation
`ds = v0 `dt + .5 a `dt^2.
This equation could have been obtained from the first two by substituting the right-hand side of the first equation for vf in the second and doing the straightforward algebraic simplification.
We note that the two most fundamental equations have the three variables vf, v0 and `dt in common. We've just observed that by eliminating vf we get the third fundamental equation of motion. We can also see that this equation doesn't help in the present situation, where we want to draw some kind of a conclusion from knowledge of `ds, a and v0. None of the three equations we have so far contains more than two of these variables among its four variables, and hence none can be solved for one of the remaining variables.
If we eliminate `dt from the first two equations we can see the we will end up with an equation involving vf, v0, a and `ds, which contains three of the known variables and will therefore be useful in the present situation.
The equation that we get when we eliminate `dt is `ds = ( vf^2 - v0^2 ) / (2a), which we rearrange into the form
vf^2 = v0^2 + 2 a `ds.
This is the fourth fundamental equation of motion.
We observe that we now have four equations, each with four variables, with the property that given any three of the variables v0, vf, `ds, `dt and a, at least one of these equations will contain the three and can hence be solved for the fourth.
These equations all arise from the first two; these two we understand at the intuitive level as expressing the definition of acceleration and average velocity.
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The details of the process of eliminating `dt from the two most fundamental equations are shown below.
Video clip #03Accelerating down an incline through a given distance vs. accelerating for a given time
We now pose the following question:
If a cart coasts a specific distance down a certain incline starting from rest, it will experience a certain velocity change.
Most students will agree that this argument seems persuasive, and that since the conditions seee to be the same, the velocity change will indeed be the same in both cases.
Before you read further you should carefully consider both of these arguments and decide for yourself which seems to be more persuasive.
The equations of motion settle the argument.
The equation vf = v0 + a `dt tells us clearly that if we have the same acceleration over a shorter time interval, our velocity will increase by less. The change in velocity is without a doubt a `dt.
The equation vf^2 = v0^2 + 2 a `ds, on the other hand, tells us that when a and `ds are identical, the difference in the squared velocities will be identical:
Solving for a `dt and a `ds, we obtain the equations
a `dt = vf - v0
a `ds = (vf^2 - v0^2) / 2,
which will both have profound implications later when we study momentum and energy.
Video clip #04"