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Phy 201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.2_labelMessages **
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 13 s+5 s=18 s/2=9 s
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What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
16 cm/s+40 cm/s=56 cm/s/2=28 cm/s
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How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
13 s-5 s=8 sec=change in time
8 sec*28 cm/s=224 cm
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By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 13 sec-5 sec=8 sec
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By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 40 cm/s-16 cm/s=24 cm/s
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What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): average rate=(24 cm/s)/(8 s)=3 cm/sec^2
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What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): rise=y intercept
rise=40 cm/s-16 cm/s=24 cm/s
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What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
run=x intercept
run=13 s-5 s=8 s
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What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): slope=rise/run
slope=(24 cm/s)/(8 s)
slope=3 cm/sec^2
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What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): The slope is the same thing as the average rate. The slope therefore represents the average of change.
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&#Your work looks very good. Let me know if you have any questions. &#
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Note: When the instruction says that your response should start in the next line, be sure it does start on its own line. I review thousands of responses every night, and responses need to go where my eye expects to find them.
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