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Phy 201
Your 'cq_1_09.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_09.1_labelMessages **
A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds.
What are its average velocity, final velocity and acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
ds=20 cm
v0=0 cm/s
dt=2 s
vAve=20 cm/2 s=10 cm/s
vf=10 cm/s*2=20 cm/s
a=20 cm/s/2=10 cm/s^2
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If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
dt= 2*.03=.06+2=2.06 s
vAve=20 cm/2.06=9.71 cm/s
vf=9.71 cm/s*2=19.42 cm/s
a=19.42 cm/s/2.06 s=9.43 cm/s^2
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What is the percent error in each?
answer/question/discussion: ->->->->->->->->->->->-> :
Percent error of velocity:
9.71/10=.971*100=97.1
100-97.1=2.9%
Percent error of time:
2/2.06=.971*100=97.1
100-97.1=2.9%
Roughly about a 3% error for both quantities.
Therefore, there is about a 6% error for acceleration.
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If the percent error is the same for both velocity and acceleration, explain why this must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
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If the percent errors are different explain why it must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
They are different because velocity had a 3% error and when finding acceleration you must divide by time which also had a 3% error. This makes the acceleration have a total of 6% error.
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