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Phy 201
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
F=m*a
F=12 kg*3 m/s^2=26 N
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What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
a=20 N/4 kg=5 m/s^2
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If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
If we solve for a based on the force and weight we are given we find:
a=20 N/10 kg=2 m/s^2
We calculated 2 m/s^2 and we were given 1.5 m/s^2
Therefore, there is an opposing force
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What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
If I am pushing with a force of 20 N and the acceleration of the object is 1.5 m/s^s, then we can figure out that the opposing force is -5 N because:
20 N + (-5N) = 15 N
Fnet = 15N
&#Your work looks very good. Let me know if you have any questions. &#