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Phy 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
5 kg*9.8 m/s^2=49 N
6 kg*9.8 m/s^2=58.8 N
58.8 N-49 N=9.8 N
a=9.8 N/11 kg=.89 m/s^2
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If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
dv=.9 m/s^2*1 s=.9 m/s
dv=vf-v0
vf=-.9 m/s
1 second later the 5 kg object will be descending by .9 m/s instead of 1.8 m/s.
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During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
During the first second interval the acceleration is positive and the velocity is still negative. Acceleration and velocity are in opposite directions. This will lead to the object slowing down.
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15 minutes
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Very good responses. Let me know if you have questions.