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course PHY121
3.9.11 at 10:33am
Reason out the quantities v0, vf, Dv, vAve, a, Ds and Dt: If an object’s velocity changes at a uniform rate from 11 cm/s to 15 cm/s as it travels 117 cm, then what is the average
acceleration of the object?
Using the equations which govern uniformly accelerated motion determine vf, v0, a, Ds and Dt
for an object which accelerates through a distance of 117 cm, starting from velocity 11 cm/s
and accelerating at .444 cm/s/s.
v0=11cm/sec
vf=15cm/sec
'ds=117cm
'dv=15cm/s-11cm/s=4cm/s
vAve=(15cm/s+11cm/s)/2=13cm/s
'dt='ds/vave
=117cm/13cm/s=4cm/s
a-Ave='dv/'dt
=4cm/s/9sec=0.444cm/s^2"
&#Very good responses. Let me know if you have questions. &#