#$&*
PHY121
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
#$&*
0.75m/0.05 = 15
10m/8sec = 1.25m/sec
10m/5sec = 2m/sec
2m/sec-1.25m/sec = 0.75m
Slope 0.10 - slope 0.05 = 0.05 difference
Not sure what untis would go with the 15 on line 1?
** **
10 minutes
** **
@& You haven't calculated accelerations, but you have done most of what would be required to find the average rate of change of average velocity with respect to slope.
If you divide the change in average velocity by the change in slope, you get the average rate of change of average velocity with respect to slope.
Now find the accelerations on the two slopes, and follow the same reasoning to get the requested result.
&#Please see my notes and, unless my notes indicate that revision is optional, submit a copy of this document with revisions and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes.
If my notes indicate that revision is optional, use your own judgement as to whether a revision will benefit you. &#