Assignment 11 Random

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course Phy 121

3.26.11 at 10:15pm

If the slope of a graph of the acceleration of a cart vs. the number of paper clips attached by a string and suspended over a pulley is ( 18 cm/s2) / clip, and if the slope of a graph of number of paper clips needed to maintain equilibrium vs. ramp slope is 59 clips / unit of ramp slope, then how many cm/s2 of acceleration should correspond to 1 unit of ramp slope? If 57 clips are necessary to match the mass of the cart, then if we could apply this force to the cart without the extra mass of all those clips, what would be the acceleration of the cart?Since slope is 18cm/s^2 per clip and there are 59 clips per unit, there should be 18cm/s^2 of acceleration per unit of ramp slope.

a = Fnet/m

Acceleration would equal the net force divided by total mass, not including extra mass from additional clips.

((m of 57 clips + m of cart)*9.8m/s^2) / mass of cart alone

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Self-critique (if necessary):

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Self-critique rating:

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@& You know the acceleration per clip, and the number of clips per unit of slope.

Acceleration 18 cm/s^2 corresponds to each clip, and 57 clips correspond to 1 unit of slope. The number of cm/s^2 per unit of slope is therefore 18 * 57.

With units the calculation looks like this:

18 (cm/s^2) / clip * 57 clips / unit of slope = 1030 cm/s^2 / unit of slope, approx..

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