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PHY 121
Your 'cq_1_20.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The situation here is similar to that depicted above, though the distances of the rubber
bands from the center are different. The die on which the strap rotates is not visible,
but is attached to the tabletop; the blue push pin constrains the system to rotate about a
vertical axis through the center of the die.
The problem:
The metal strap used in the Angular Velocity of a Strap experiment is constrained by a
vertical push pin to rotate about a hole in a die. The die is glued in place to a massive
tabletop. A rubber band is attached to a point 15 cm from the axis and stretched so that
it exerts a force of 3 Newtons, directed perpendicular to the rod. If this force is
unopposed it will accelerate the system rapidly. You want to attach a second rubber band 5
cm from the axis to prevent the system from rotating.
How much force will that rubber band have to exert?
answer/question/discussion: ->->->->->->->->->->->-> :
It will have to exert an equal amount of force as the one that is 15 cm to keep the strap stationary.
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Once both of these forces are in place and the system is stationary, what (if anything)
will happen if the glue holding the die to the tabletop comes loose?
answer/question/discussion: ->->->->->->->->->->->-> :
Nothing will happen. If the system is at rest when the glue comes unstuck, it will remain still unless it tumbles over.
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5 minutes
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&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
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