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PHY 121
Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a
rubber band chain which exerts a tension force of 2.5 Newtons on the ball.
What is the weight of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
9.8m/sec^2 * 0.4kg = 3.92kg
@& When you multiply a quantity in m/s^2 by a quantity in kg you don't get kg, you get kg * m/s^2.
kg is the unit of mass, m/s^2 the unit of acceleration
force = mass * acceleration, so the resulting unit is the unit of force
thus kg m/s^2 = N
and the force here is 3.92 N.*@
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What is the buoyant force on the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
It will be equal to the weight of the water it displaces. Going out on a limb, I'll guess 2.5N, the tension force on the ball.
@& The weight acts downward, the tension force and the buoyant force act upward.
All these forces add up to zero.
assuming upward to be positive, the tension s +2.5 N and the weight is -3.92 N.
In order for these two forces and the buoyant force to add up to zero, what must therefore be the buoyant force?*@
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What therefore must be its volume?
answer/question/discussion: ->->->->->->->->->->->-> :
v * 9.8m/sec^2 = 2.5N
@& volume * acceleration doesn't equal force*@
v = 0.255
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What is its density?
answer/question/discussion: ->->->->->->->->->->->-> :
0.4kg/0.255ml = 1.57
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10 minutes
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&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
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