If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.

Your solution, attempt at solution. 

If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it.  This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

017.  ``q Query 17

Question:  `q Query  problem 13.4.12  z score for KG's rebounds (.4 from bottom range 10-13)

Your solution: 

Confidence Assessment:

Given Solution: 

`aThe z score for KG is his total number of rebounds minus the mean average number of rebounds for all the players and then divided by the standard deviation. In KG' s case:

z = (489 - 538.2) / 38.8 = -1.3  **

Self-critique (if necessary):

Self-critique Rating:

Question:  `q Query  problem 13.4.30  midquartile same as median?  (Q1+Q3)/2

Your solution: 

Confidence Assessment:

Given Solution: 

`aIf the median is the actual number in the middle, the it's not necessarily equal to the mean of the first and third quartile.  There are different ways to see this.

For example suppose that in a large set of numbers, the median number is at least 2 greater than the next smaller number and 2 smaller than the next greater number.  Then if all the other numbers stay the same, but the median is increased or decreased by 1, it's still in the middle, so it's still the median.  Since all the other numbers stay the same, the first and third quartiles are the same as before, so (Q1 + Q3) / 2 is still the same as before.  However the median has changed.  So if the median was equal to (Q1 + Q3) / 2, it isn't any more.  And if it is now, it wasn't before.  In either case we see that the median is not necessarliy equal to the midquartile.

To be even more specific, the median of the set {1, 3, 5, 7, 9, 11, 13} is 7.  The median of the set {1, 3, 5, 8, 9, 11, 13} is 8.  The midquartile of both sets is the same, so for at least one of the two sets (namely the second, as you can verify for yourself) the median and the midquartile are different.  **

Self-critique (if necessary):

Self-critique Rating: