your response &&&&&&&&&&&&&&&&&&
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data from Error Analysis I: 3 19577.64 1.007813 4 19578.59 .9453125 5 19579.67 1.085938 6 19580.77 1.101563 7 19581.91 1.140625 8 19582.97 1.054688 9 19583.96 .9921875 10 19585.09 1.132813 11 19586.15 1.054688 12 19587.23 1.078125 13 19588.3 1.070313 14 19589.35 1.054688 15 19590.41 1.054688 16 19591.48 1.070313 17 19592.55 1.078125 18 19593.63 1.070313 19 19594.7 1.070313 20 19595.73 1.039063 21 19596.82 1.085938 22 19597.88 1.054688 23 19598.92 1.046875 24 19600.02 1.101563 25 19601.06 1.039063 26 19602.15 1.085938 27 19603.24 1.09375 28 19604.28 1.039063 29 19605.34 1.054688 30 19606.41 1.070313 31 19607.51 1.101563 32 19608.59 1.078125 mean: 1.03 mean of 6 sample: 1.07 standard deviation: .0346 Is not less than. #$&* You may download the data program or run it directly from the site. Note the following: The program is in an ongoing process of development and some of the buttons might not work. However the operations you are instructed to perform below have been tested and do work. When you run the program you might encounter some message boxes at the beginning; these boxes have been inserted to prompt the inclusion of some additional features in the program. If you do encounter these message, you may safely just click through them messages until just the form appears. The program is easy to use and is very efficient for its purpose. Additional features will be added as needed. Run the program and click through any extraneous messages. (If necessary you might need to click on the maximize button to maximize the size of the form and make all the buttons visible, but this should not be an issue.) Delete all information in the textbox (you can use the Clear button near the lower right corner of the box), and copy your TIMER data into the box. You may use either the data you have retained from the TIMER program or the data as posted on your access page (data should be posted if you submitted the program in a timely fashion). Your data will be in 3 columns. Manually delete all the information except the 30 time intervals, so there are 30 lines each with a single number in the textbox, the number representing the time interval in seconds (if your original data is in a spreadsheet you could just copy the single column corresponding to the time intervals). Copy and paste these 30 lines into a separate text editor or word-processing program so you can use them again later. Click on the Mean and Standard Deviation button. A message box will appear asking you to confirm that your data is entered in the necessary format. Then the program will very quickly display the mean and standard deviation of that distribution. What are the mean and standard deviation of your 30 time intervals, as reported by the program? Report below, using two tab-delimited numbers in the first line. Starting in the next line give a brief explanation of what your numbers mean and how you obtained them. After that explanation, include a copy of your data set for reference.your response &&&&&&&&&&&&&&&&&&
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mean of 30 intervals: 1.065 standard deviation:0.03786 how obtained:copied my data into data program, deleted unneccessary informaion and then clicked mean and standard deviation button #$&* Investigate 'first differences' of 30-interval data Now restore your original 30 time intervals to the box. You will have to do this manually, clearing the contents of the box and then copying and pasting the data from the text editor or word processor where you stored it before. Make sure your data also stays in that location, because you'll need it at least once again. Click on the First Difference button. You will see a report of the differences between your successive time intervals. Give the first three differences below, in the first line in comma-delimited format. Starting at the second line answer the two questions: Are all the differences between your time intervals all different, or do some occur more than once? Where have you see this information before and what does it mean?your response &&&&&&&&&&&&&&&&&&
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first three differences of clock times:-.06250,.1406,.01563 are differences all the same: no where seen before:some appear more than once #$&* Sum your 30 time intervals and speculate on meaning Restore your original 30 intervals to the box. Click on the Running Sum button. Scroll down and take a quick look at the entire report. Give your first three running sums below, in the first line in comma-delimited format. Starting at the second line, explain how you think these numbers were calculated from the time intervals, and what these numbers might mean.your response &&&&&&&&&&&&&&&&&&
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running sum of intervals, first three sums:1.008,1.953,3.039 explanation of how running sums were obtained:it adds each number to the previous sum and tells the new sum #$&* Analyze the first difference of the running sums, and the first difference of this result Delete everything but the single-column report of the running sums, so the data box contains just the running sums with one sum on each line, and click on the 'first difference' button. Report your first three new numbers below, in the first line in comma-delimited format. Describe what you see and what might be the meaning of the new numbers. Suggestion: look at your original 30 time intervals. How do you think the new numbers were calculated, where have you seen them before, and why do they come out the way they do?your response &&&&&&&&&&&&&&&&&&
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first difference of running sums, first three numbers:1.008,.945,1.086 description and meaning:this shows the difference in the running sums explanation of how numbers were calculated:takes the first sum subtracts from the second and tells the difference. Continues all through the list #$&* Again isolate only the single-column report and again click on First Differences. Report your first three new numbers below, in the first line in comma-delimited format. How do you think the new numbers were calculated, where have you seen them before, and why do they come out the way they do?your response &&&&&&&&&&&&&&&&&&
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first three numbers from first difference:.063,.141,.016 how calculated: using data program, it subtracts 1st from 2nd and displays sum. continues through list #$&* Find difference quotients for a new set of data and speculate on the meaning of the difference quotient Clear the box then copy the following 4 lines into the textbox: 0, 0 10,10 20,25 30,45 Click on the Difference Quotient button. Report below the three new numbers you see, reporting your numbers in the first line in comma-delimited format. In the second line speculate on how the program might have calculated these numbers.your response &&&&&&&&&&&&&&&&&&
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difference quotient from sample data: how you think the results were calculated: #$&* The information in the table 0, 0 10,10 20,25 30,45 represents the position of an object rolling down an incline vs. clock time, with position in meters and clock time in seconds. Recall that according to our 'y vs. x' convention, in a position vs. clock time table the clock time is in the first column. How far did the object travel in the first time interval? How much time elapsed while it traveled through this distance? What therefore was its average speed during this time interval? Report your numerical answers to these three questions in the first line below, in comma-delimited format. Answer the same questions for the second time interval, and report in the second line, using the same format as in the first. Answer the same questions for the third time interval, and report in the third line, using the same format as in the first. Starting in the fourth line, explain how you obtained your results. Then explain once more what the 'difference quotient' operation does to two columns of numbers.your response &&&&&&&&&&&&&&&&&&
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distance during first interval: 10 elapsed time while traveling this distance: 10 average speed during interval:1 distance during second interval: 15 elapsed time while traveling this distance: 10 average speed during interval:1.5 distance during third interval: 20 elapsed time while traveling this distance: 10 average speed during interval:2 explanation: shows distance between intervals, time elapsed during intervals, and average speed. explanation of 'difference quotient' operation: takes information in correct format and displays the difference quotients in a single column. #$&* Select and analyze 5 random intervals from 30-interval data, using the data program to find mean and standard deviation Using a coin according to the following instructions, you will now select 5 intervals randomly from your 3-interval data. You will do this by generating 5 numbers corresponding to the numbers of your data point. The process should take only a couple of minutes: Using the coin you will generate a series of numbers between 0 and 31. Note that there are 32 numbers between 0 and 31. This process can generate 32 possible numbers. If you generate a number you have generated before you will discard it and generate an alternative. If you generate a number that does not correspond to one of your intervals (probably 1-20 or 1-19) you will discard that number. You will continue until you have generated 5 numbers that haven't been discarded. To generate each number will require 5 flips of your coin. You will write down 5 numbers. Your first flip is worth 1. Flip the coin. If you get Heads write down the number 1. If you get tails write down 0. Whichever number you write down will be at the top of a column. Your second flip is worth 2. Flip the coin a second time. If you get Heads write down the number 2. If you get tails write down 0. This number does in the column below the previous. The third, fourth, and fifth flips are respectively worth 4, 8 and 16 on Heads, 0 if you get Tails. You should now have five numbers in your column. Add them up. The result will be not less than 0 + 0 + 0 + 0 + 0 and not more than 1 + 2 + 4 + 8 + 16 = 31. Go ahead and generate your first number according to these instructions. If the number is between 1 and the number of intervals you observed (e.g., between 1 and 30, or between 1 and 29), circle the number. Now generate another number, using the same procedure with 5 flips of the coin. If this number is between 1 and your number of intervals (e.g., between 1 and 30), and if it does not duplicate the first number you generated, circle it. Continue this process, generating totals between 0 and 31 and circling those that lie in the correct range and do not duplicate any your previous numbers. Stop when you have generated 5 distinct numbers within the appropriate range. Now select the time intervals corresponding to the numbers you have generated (e.g., if you had a 30-interval set and your numbers were 23, 8, 11, 19, 5 and 22 you would select the 23d, 8th, 11th, 19th, 5th and 22d time intervals). Clear, then put these 5 time intervals into the textbox. Note that you will put time intervals into the textbox, not the numbers you have generated between 0 and 31. Click on the Mean and Standard Deviation button. In the first line below, report the five random numbers you generated, in comma delimited format. In the second line below, report the five time intervals you put into the box, in comma delimited format. In the third line, report the mean and the standard deviation in comma-delimited format. Starting in the fourth line give a brief explanation of what your numbers mean and they were obtained. Optional comments may be added.your response &&&&&&&&&&&&&&&&&&
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your five random numbers:7,13,16,20,24 your five intervals:.9921875,1.054688,1.070313,1.054688,1.085938 mean and standard deviation:1.052,0.03563 explanation: followed directions and listed values #$&* In three lines report the following numbers: By how much does the mean of your 5-interval sample differ from the mean of the entire data set of 30 intervals? What is the standard deviation of the 30-interval set? What is the first number you reported as a percent of the second. That is, what is the difference between your sample and the entire data set, as a percent of the standard deviation of the data set? Starting in the fourth line give a brief explanation of what your numbers mean and how you obtained themyour response &&&&&&&&&&&&&&&&&&
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difference of means:.02 standard deviation of 30-interval set:.0346 first number as percent of second:58 percent explanation and meanings: this random sample is more accurate #$&* Analyze a set of 'made-up' time intervals and look at their distribution The set of numbers given below represents a set of 30 'made-up' quick-click time intervals. You will answer a few questions about this data set, including the mean and standard deviation of a 5-interval random sample. Later the results of all students will be compiled and used to demonstrate the 'sample standard deviation', which is an important statistical characteristic of sample and very relevant to interpretation of experimental results. .1752 .172 .1979 .1991 .176 .1711 .1664 .1665 .1858 .1764 .1765 .1885 .173 .1853 .1683 .1674 .1833 .1632 .1783 .1962 .1704 .1914 .1751 .1715 .1967 .1852 .1851 .1771 .1639 .1824 .1877 Copy these numbers into a cleared textbox, click on Mean and Standard Deviation, and report their mean and standard deviation in comma-delimited format in the first line below. Starting in the next line give a brief explanation of what your numbers mean and how you obtained them.your response &&&&&&&&&&&&&&&&&&
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mean and standard deviation of given data: There are 31 numbers listed above not 30. However, based on the 31 sample the mean is .1791, .01025 explanation and meanings: the average is .1791 and the standard dev. is .01025 #$&* below, enter the following numbers, one to a line, in the given order: The number which is two standard deviations less than the mean. The number which is one standard deviation less than the mean. The number which is equal to the mean. The number which is one standard deviation more than the mean. The number which is two standard deviations more than the mean. Starting in the next line give a brief explanation of what your numbers mean and how you obtained themyour response &&&&&&&&&&&&&&&&&&
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two standard deviations less than the mean:.1586 one standard deviation less than the mean: .1689 the mean:.1791 one standard deviation more than the mean:.1894 two standard deviations more than the mean:.1997 explanation and meanings:setting up marks for a bell curve. #$&* below, report each of the following numbers, one number to each line: The number of the given time intervals which are less than the number which is two standard deviations less than the mean: The number of the given time intervals which lie between two standard deviations less than the mean and one standard deviation less than the mean: The number of the given time intervals which lie between one standard deviation less than the mean and the mean: The number of the given time intervals which lie between the mean and one standard deviation more than the mean: The number of the given time intervals which lie between one standard deviation more than the mean and two standard deviations more than the mean: The number of the given time intervals which are greater than the number which is two standard deviations more than the mean: Starting in the 7th line give a brief explanation of what your numbers mean and how you obtained them; as usual you may include optional comments:your response &&&&&&&&&&&&&&&&&&
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number of given intervals which are less than the number which is two standard deviations less than the mean:0 number of given intervals which are between two standard deviations less than the mean and one standard deviation less than the mean:6 number of given intervals which are between one standard deviation less than the mean and the mean:12 number of given intervals which are between the mean and one standard deviation more than the mean:8 number of given intervals which are between one standard deviation more than the mean and two standard deviations more than the mean:5 number of given intervals which are greater than the number which is two standard deviations more than the mean:0 explanation and comments:counted how many fall in each standard deviation #$&* below, report each of the numbers you reported above, but expressed as a percent of the 30 intervals (rounded to the nearest percent). For example, the number 10 would be 33% of 30. Include a brief explanation of what your numbers mean and how you obtained themyour response &&&&&&&&&&&&&&&&&&
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percent of given intervals which are less than the number which is two standard deviations less than the mean:0 percent of given intervals which are between two standard deviations less than the mean and one standard deviation less than the mean:19 percent of given intervals which are between one standard deviation less than the mean and the mean:39 percent of given intervals which are between the mean and one standard deviation more than the mean:26 percent of given intervals which are between one standard deviation more than the mean and two standard deviations more than the mean:16 percent of given intervals which are greater than the number which is two standard deviations more than the mean:0 explanation and comments:took each answer from previous question and divided by 31 #$&* Perform a similar analysis with your 30-interval data Return to your own 30 time intervals. Count the numbers in each range (less than mean - 2 std dev, between mean - 2 std dev and mean - 1 std dev, between mean - 1 std dev and mean, etc.), using the mean and standard deviation of that data set. Report each number as a percent of your total number of intervals, one number in each of the first six lines below. Starting in the 7th line give a brief explanation of what your numbers mean and how you obtained themyour response &&&&&&&&&&&&&&&&&&
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number and percent of given intervals which are less than the number which is two standard deviations less than the mean:1,3 number and percent of given intervals which are between two standard deviations less than the mean and one standard deviation less than the mean:3,10 number and percent of given intervals which are between one standard deviation less than the mean and the mean:13,43 number and percent of given intervals which are between the mean and one standard deviation more than the mean:8,27 number and percent of given intervals which are between one standard deviation more than the mean and two standard deviations more than the mean:1,3 number and percent of given intervals which are greater than the number which is two standard deviations more than the mean:1,3 explanation and comments:some of my numbers fell directly on the cutoff points #$&* In a standard 'normal' distribution, we expect that the respective percents in the six ranges will be about 2%, 14%, 34%, 34%, 14% and 2%. In a very large sample of data (say, at least tens of thousands of data points), if the data are in fact distributed normally, we expect actual results to very nearly reflect this distribution. If a large distribution does not closely match the expected results, we suspect that something in the system or in our observation process in fact deviates from the 'standard normal' expectation. Not everything we observe does in fact follow the standard normal pattern. You 3-interval results might or might not be expected to follow a standard normal distribution. If the data sample is not very large, the chance fluctuations in the distribution could have a significant effect on the percents, which in that case may not be all that close to the expected distribution. However in a medium-sized sample of 30 or so, we definitely expect more observations to lie in the middle two ranges and in either of the outer ranges, and we aren't too surprised if no results at all appear in the outermost ranges (more than 2 standard deviations from the mean). Based on the percents you reported and the percents quoted above, by how much would you say your actual 30-interval results deviated from the standard normal distribution? Did your results deviate enough to make you suspect that your clicks were not normally distributed about their mean?your response &&&&&&&&&&&&&&&&&&
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the majority of my information falls between 1 standard dev. below the mean and the mean. My curve won't exactly fit a normal distribution. #$&* Answer the same question for the 30 made-up time intervals given earlier.your response &&&&&&&&&&&&&&&&&&
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I think the made up one fits the bell curve better. #$&* Compare your distribution with the standard normal distribution We will in a subsequent exercise learn to sketch a standard normal curve, and to represent our information using this sketch. For the present, simply copy this figure below and label it as indicated below: There are five vertical lines on the graph, representing respectively mean - 2 * std dev, also labeled z = -2 mean - 1 * std dev, also labeled z = -1 mean - std dev, also labeled z = 0 mean + 1 * std dev, also labeled z = 1 mean + 2 * std dev, also labeled z = 2. Label the x axis with the z numbers -2, -1, 0, 1 and 2. Below these labels, place the respective numbers you obtained earlier for your 30-interval results, the numbers corresponding to mean - 2 * std dev, mean - 1 * std dev, etc.. The five lines divide the region between the curve and the x axis into six smaller regions. Each of these regions will include either 2%, 14% or 34% of the total area between the curve and the x axis. Within each region, write your best estimate of the number that represents its area as a percent of the total. below: Indicate in the first line in comma-delimited format the numbers you placed in the regions, from left to right. Indicate in the second line the x-axis labels corresponding to z = -2, -1, 0, 1 and 2 for the mean and standard deviation you obtained for your data. Starting in the third line give a brief explanation of what your numbers mean and how you obtained them.your response &&&&&&&&&&&&&&&&&&
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numbers representing percents in each of six regions: 2,14,34,34,14,2 suppose to be. mine is 3,10,43,27,3,3 x-axis labels for your data:1.01,1.04,1.07,1.10,1.13 explanation: mine are incorrect, the bell curve percentages are suppose to add up to 100percent. #$&* *#&!