Open Query 19

course Phy 121

019. `query 19*********************************************

Question: `qQuery class notes #20

Explain how we calculate the components of a vector given its magnitude and its angle with the positive x axis.

Your solution: x vector=magnitude*costheta and y vector=magnitude*sintheta

Theta=arctan(y/x). and total magnitude=Pythagorean theorem.

confidence rating #$&*

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Given Solution:

`a** STUDENT RESPONSE:

x component of the vector = magnitude * cos of the angle

y component of the vector = magnitude * sin of the angle

To get the magnitude and angle from components:

angle = arctan( y component / x component ); if the x component is less than 0 than we add 180 deg to the solution

To get the magnitude we take the `sqrt of ( x component^2 + y component^2) **

Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `qExplain what we mean when we say that the effect of a force is completely equivalent to the effect of two forces equal to its components.

Your solution: That’s the same thing as if two people pulled in Fx and Fy direction.

Confidence rating #$&*: 3

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Given Solution:

`a** If one person pulls with the given force F in the given direction the effect is identical to what would happen if two people pulled, one in the x direction with force Fx and the other in the y direction with force Fy. **

Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `qExplain how we can calculate the magnitude and direction of the velocity of a projectile at a given point.

Your solution: Determine Vx and Vy then use the Pythagorean Theorem to determine velocity. The angle is the same as the previous question.

confidence rating #$&*

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Given Solution:

`a** Using initial conditions and the equations of motion we can determine the x and y velocities vx and vy at a given point, using the usual procedures for projectiles.

The magnitude of the velocity is sqrt(vx^2 + vy^2) and the angle with the pos x axis is arctan(vy / vx), plus 180 deg if x is negative. **

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `qExplain how we can calculate the initial velocities of a projectile in the horizontal and vertical directions given the magnitude and direction of the initial velocity.

Your solution: V0x=vcostheta and V0y=vsintheta

confidence rating #$&*

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Given Solution:

`a** Initial vel in the x direction is v cos(theta), where v and theta are the magnitude and the angle with respect to the positive x axis. Initial vel in the y direction is v sin(theta). **

Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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&#This looks good. Let me know if you have any questions. &#

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