course Phy 201 ¥Ãý¸’Õ»q½|ÏÆ¿žëxø¯³Û‰çŒ¦RÁüÜ{Jöassignment #000
......!!!!!!!!...................................
20:41:33 The Query program normally asks you questions about assigned problems and class notes, in question-answer-self-critique format. Since Assignments 0 and 1 consist mostly of lab-related activities, most of the questions on these queries will be related to your labs and will be in open-ended in form, without given solutions, and will not require self-critique. The purpose of this Query is to gauge your understanding of some basic ideas about motion and timing, and some procedures to be used throughout the course in analyzing our observations. Answer these questions to the best of your ability. If you encounter difficulties, the instructor's response to this first Query will be designed to help you clarify anything you don't understand. {}{}Respond by stating the purpose of this first Query, as you currently understand it.
......!!!!!!!!...................................
RESPONSE --> To let you know we understand whats going on.
.................................................
......!!!!!!!!...................................
20:42:45 If, as in the object-down-an-incline experiment, you know the distance an object rolls down an incline and the time required, explain how you will use this information to find the object 's average speed on the incline.
......!!!!!!!!...................................
RESPONSE --> divide the distance by the time confidence assessment: 3
.................................................
......!!!!!!!!...................................
20:45:13 If an object travels 40 centimeters down an incline in 5 seconds then what is its average velocity on the incline? Explain how your answer is connected to your experience.
......!!!!!!!!...................................
RESPONSE --> 40/5=8cm/s. I used this to find my avg. speed of my marble going down the book. confidence assessment: 3
.................................................
......!!!!!!!!...................................
21:44:30 If the same object requires 3 second to reach the halfway point, what is its average velocity on the first half of the incline and what is its average velocity on the second half?
......!!!!!!!!...................................
RESPONSE --> Take the rise 20cm or halfway point divided by the run 3s and you get 6.7cm/s on the first half. And on the second half of the incline you have a rise of 20cm divided by the run of 2s which gives you 10cm/s confidence assessment: 2
.................................................
......!!!!!!!!...................................
21:51:33 Using the same type of setup you used for the first object-down-an-incline lab, if the computer timer indicates that on five trials the times of an object down an incline are 2.42 sec, 2.56 sec, 2.38 sec, 2.47 sec and 2.31 sec, then to what extent do you think the discrepancies could be explained by each of thefollowing: {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioningthe object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
......!!!!!!!!...................................
RESPONSE --> Im not for sure exactly what your looking for here. I do believe that all of the factors listed have some effect on the the final times. confidence assessment: 1
.................................................
......!!!!!!!!...................................
21:54:05 How much uncertainty do you think each of the following would actually contribute to the uncertainty in timing a number of trials for the object-down-an-incline lab? {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated bLine$(lineCount) =with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
......!!!!!!!!...................................
RESPONSE --> All would probally account for a couple hundredth of a second confidence assessment: 1
.................................................
......!!!!!!!!...................................
22:00:57 What, if anything, could you do about the uncertainty due to each of the following? Address each specifically. {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actualdifferences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
......!!!!!!!!...................................
RESPONSE --> A. get a precision timer B have a push button that starts the timer and releases the ball at the same time C.n/a D.develop a mechanical device to hold it at the same position E.install an electric photoeye that reads the ball and triggers the timer confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:02:20 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
......!!!!!!!!...................................
RESPONSE --> less than half confidence assessment: 3
.................................................
......!!!!!!!!...................................
22:03:22 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
......!!!!!!!!...................................
RESPONSE --> because that is the intersection of the graph. the y and x intersect at this point. confidence assessment: 3
.................................................
......!!!!!!!!...................................
22:15:00 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
......!!!!!!!!...................................
RESPONSE --> That the pendulum would be long an would not get one cycle. confidence assessment: 1
.................................................
......!!!!!!!!...................................
22:17:49 On a graph of frequency vs. pendulum length, what would it mean for the graph to intersect the horizontal axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the horizontal axis)? What would this tell you about the length and frequency of the pendulum?
......!!!!!!!!...................................
RESPONSE --> There would be no cycle no matter what the length unless there is none. confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:20:36 If a ball rolls down between two points with an average velocity of 6 cm / sec, and if it takes 5 sec between the points, then how far apart are the points?
......!!!!!!!!...................................
RESPONSE --> 30cm, because at 6cm/s and it travels 5s then we need to get the product of 6cm/s*5s which is 30cm confidence assessment: 3
.................................................
......!!!!!!!!...................................
22:22:08 On the average the ball moves 6 centimeters every second, so in 5 seconds it will move 30 cm. {}{}The formal calculation goes like this: {}{}We know that vAve = `ds / `dt, where vAve is ave velocity, `ds is displacement and `dt is the time interval. {}It follows by algebraic rearrangement that `ds = vAve * `dt.{}We are told that vAve = 6 cm / sec and `dt = 5 sec. It therefore follows that{}{}`ds = 6 cm / sec * 5 sec = 30 (cm / sec) * sec = 30 cm.{}{}The details of the algebraic rearrangement are asfollows:{}{}vAve = `ds / `dt. We multiply both sides of the equation by `dt:{}vAve * `dt = `ds / `dt * `dt. We simplify to obtain{}vAve * `dt = `ds, which we then write as{}`ds = vAve *`dt.{}{}Be sure to address anything you do not fully understand in your self-critique.
......!!!!!!!!...................................
RESPONSE --> ok self critique assessment: 3
.................................................
......!!!!!!!!...................................
23:04:51 You were asked to read the text and some of the problems at the end of the section. Tell me about something in the text you understood up to a point but didn't understand fully. Explain what you did understand, and ask the best question you can about what you didn't understand.
......!!!!!!!!...................................
RESPONSE --> The percent error thing is a little confusing. Its not that I dont fully understand it, its just confusing one time you go by significant digits but then you still need to be aware of the % uncertainty.
.................................................
......!!!!!!!!...................................
23:08:07 Tell me about something in the problems you understand up to a point but don't fully understand. Explain what you did understand, and ask the best question you can about what you didn't understand.
......!!!!!!!!...................................
RESPONSE --> All problems seemed to work out well confidence assessment: 3
.................................................