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02:57:44 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> by taking the sqrt of the mean of the squared deviation confidence assessment: 3
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03:02:56 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> Its just an eyeball guess. Just trying to get the line to average out between all the data points without going through them. In doing out lab I was close to the best fit line but never got it right. people are going to look at it in different ways confidence assessment: 2
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03:12:05 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> The rate at which position is changing. because your taking measurements to get the velocity confidence assessment: 2
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03:14:54 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> ok self critique assessment: 3
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03:18:28 Given average speed and time interval how do you find distance moved?
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RESPONSE --> multiply the average speed by the time and you get the distanced moved 'ds=avg.v*'dt confidence assessment: 3
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03:18:40 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> ok self critique assessment: 3
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03:23:27 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> 'ds/avg.v='dt 10miles/5mph=2hr confidence assessment: 3
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03:26:10 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> gotcha self critique assessment: 3
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03:27:42 Given time interval and distance moved how do you get average speed?
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RESPONSE --> vavg.='ds/'dt 60ft/10s=6ft/s confidence assessment: 3
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03:28:03 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> ok self critique assessment: 3