course Phy 201

The problem:A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.

What will be its velocity after the 3 seconds has elapsed?

answer/question/discussion:

Since acceleration is `dv/3secs we will flip the equation to get the `dv.

8cm/s^2*3secs=24cm/s. Now we know `dv we can add this to v0 to get the vf.

12cm/s+24cm/s=36cm/s

Assuming that acceleration is constant, what will be its average velocity during this interval?

answer/question/discussion:

Since we know vo and vf we can find vAve.

(12cm/s+36cm/s)/2=24cm/s

How far will it travel during this interval?

answer/question/discussion:

vAve*`dt=`ds

24cm/s*3secs=72cm