Phy 201
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion:
Knowing F=m*a and we know mass and accerlerration we can fill in the numbers.
F=12kg*3m/s^2
F=36kg m/s^2
F=36newtons
What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion:
Fnet=m*a knowing m and Fnet we can rearrange the equation to find a
a=Fnet/m
a=20kg m/s^2/4kg
a=5(kg/kg)m/s^2
a=5m/s^2
If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion:
If you use the equation F=m*a 10kg * 1.5m/s^2 does not equal 20newtons
What is the total of all those forces and in what direction does this total act?
answer/question/discussion:
In the previous question we found that the m and a =15newtons so this means we have a difference of 5 newtons. Fnet=F+Ff then we have a total of Fnet of 25 newtons.So to get the 15 newtons we would have 20newtons of F pushing the object in the direction of the object and 5 newtons in opposite direction of the object.
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15mins
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&#Very good work. Let me know if you have questions. &#