Phy 201
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Sketch a vector representing a 10 Newton force which acts vertically downward.
Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion:
What are the x and y components of the equilibrant of the force?
answer/question/discussion:
Since the downward force will be at 270deg and the angle of the vector is at 250deg we have a difference of 20deg. Now if we use the L cos(theta) and sin we get the x,y components. 10newtons*cos(20deg)=9.4newtons=x and 10newtons*sin(20deg)=3.4newtons=y. Since we want to know the equilibrant of the force it will be x=-9.4newtons and y=-3.4newtons
Better to figure the components of the force as 10 N * cos(250 deg) = -9.4 N and 10 N * sin(250 deg) = -3.4 N. Then take opposite signs to get the equilibrant.
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20min
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&#Your work looks good. See my notes. Let me know if you have any questions. &#