Phy 201
Your 'torques' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Your optional message or comment: **
** Positions of the three points of application, lengths of systems B, A and C (left to right), the forces in Newtons exerted by those systems, description of the reference point: **
2,9.5,13.3
8.0,8.1,8.5
.89,2.85,1.90
The left most point on my horizontal line
I took the lengths and compared it to my calibration chart and matched up the length with the newtons from the dominos.
The first line is the distance the rubber bands were hooked from my reference point from left to right. The second line is the lengths of the rubberbands in cm and the third line is the force in newtons exerted by both rubberbands.
** Net force and net force as a percent of the sum of the magnitudes of all forces: **
.06
2
The first line is the net force and I got this by adding all the forces together. Then the second line is the percent of the magnitude of all three forces which I was not for sure what to do but used the pythag. theorem on all three forces.
** Moment arms for rubber band systems B and C **
7.5,3.8
The first number is the distance in cm from rubberband point b on the horizontal line to point a,and the second number is the distance from point a to point c
** Lengths in cm of force vectors in 4 cm to 1 N scale drawing, distances from the fulcrum to points B and C. **
3.6,11.4,76
7.5,3.8
The first line is lengths in cm of 4cm per newton. I took the newtons and multiplied by 4 to get the lengths. The secon line is in cm and is the distance from the fulcrum to point b and the to point c
** Torque produced by B, torque produced by C: **
6.7,-7.2
The first number is the torque of rubberband b and the second number is the torque of rubberband c. I got these numbers by multiplying the force of rubberband and the moment-arm.
** Net torque, net torque as percent of the sum of the magnitudes of the torques: **
.5
5%
I added the two torques together to get the net torque then took the two torques and used the pythag. theorem to find the magnitude then divided the net torque by the magnitude.
The first number is the net torque and the second number is the percent of the magnitude
** Forces, distances from equilibrium and torques exerted by A, B, C, D: **
1.71,0,0
-1.9,1.5,-2.9
-.90,11.4,-10.3
1.33,14.2,18.9
The four lines are represented by rubberbands a,b,c,d in that order. The first number in each row is the force in N on each rubberband, the second number is the distance in cm from the leftmost force and the third number is the toque in N cm. I measured the distance of all rubberbands from the leftmost force and got the forces from my rubberband calibration sheet and the torque by multipying the distance by the force
** The sum of the vertical forces on the rod, and your discussion of the extent to which your picture fails to accurately describe the forces: **
.24
My picture is the same as shown above in the lab. with two forces acting in the clockwise direction and two forces in the counterclockwise direcion keeping the rod horizontal.Its not exactly right but it is very close.
** Net torque for given picture; your discussion of whether this figure could be accurate for a stationary rod: **
8.8
The right side of the rod is would be picked up in the air. No becuse your not including the other torques
** For first setup: Sum of torques for your setup; magnitude of resultant and sum of magnitudes of forces; magnitude of resultant as percent of sum of magnitudes of forces; magnitude of resultant torque, sum of magnitudes of torques, magnitude of resultant torque as percent of the sum of the magnitudes: **
5.8
4.1,9.1
.45
23,24.1,.96
The first line is the resultant torque. This was obtained by adding up all the torques.The second line is the magnitude force and sum of magnitudes of all forces. I got the magnitude of the resultant force by adding both positives and both negetives and using those numbers in the pythag, theorem. The sum of the magnitude of all forces was obtained by taking the the positive of rubberband a and the negetive of rubberband b and finding the magnitude and adding that to the quanity of the magnitude of rubberband c and d. The third line is the resultant force in percent form. I got that by dividing the magnitude of the resultant force by the sum of the magnitude of all forces. The fourth line are the same three quanities as lised above but for the torque
** For second setup: Sum of torques for your setup; magnitude of resultant and sum of magnitudes of forces; magnitude of resultant as percent of sum of magnitudes of forces; magnitude of resultant torque, sum of magnitudes of torques, magnitude of resultant torque as percent of the sum of the magnitudes: **
2.3
5.2,5.3
.99
25.2,34.8,.74
The first line is the sum of torque.The second line from left to right is the magnitude of the resultant force and the second line is the magnitude of all forces.The third line is the magnitude of the resultant force in percent of the sum of magnitude of all forces. The fourth line from left to right is the same as above except it is for the torque. i got these numbers by doing the same process as in the previous setup
** In the second setup, were the forces all parallel to one another? **
To me they all seemed to still be parallel. If there was an angle it was not noticeable, maybe 5degrees.The rubberband has a slight angle it has tobecause the rod is not horizontal anymore.I based my estimates on the second setup having a slopecompared to the horizontal setup.
** Estimated angles of the four forces; short discussion of accuracy of estimates. **
The angle of rubberband a=95deg,b=85deg,c=85,d=95
I guessed at my estimates they are off probally off +-2deg or more
** x and y coordinates of both ends of each rubber band, in cm **
** Lengths and forces exerted systems B, A and C:. **
** Sines and cosines of systems B, A and C: **
** Magnitude, angle with horizontal and angle in the plane for each force: **
** x and y components of sketch, x and y components of force from sketch components, x and y components from magnitude, sine and cosine (lines in order B, A, C): **
** Sum of x components, ideal sum, how close are you to the ideal; then the same for y components. **
** Distance of the point of action from that of the leftmost force, component perpendicular to the rod, and torque for each force: **
** Sum of torques, ideal sum, how close are you to the ideal. **
** How long did it take you to complete this experiment? **
3hrs
** Optional additional comments and/or questions: **
Very well done. Let me know if you have any questions.