Phy 201
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of
radius 20 cm.
What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion:
We know the magnitude of acc.is a=v^2/r so we have a=(.3m/s)^2/.2m,a=.45m/s^2 and the
direction is directed at the center of the circle
What is the magnitude and direction of the centripetal force required to keep it moving
around this circle?
answer/question/discussion:
T find the magnitude of the Fcent we have Fcent=m(v62/r),
Fcent=.11kg((.3m/s)^2/.2m),Fcent=.05N. The force also wil be directed at the center of the
circle if its speed is constant
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15mins
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&#Your work looks very good. Let me know if you have any questions. &#