course Mth 152 »ÒÊfØ„ðywÆÍ^¡yì¼œí¨¿“‰³ïassignment #004
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10:30:02 Query 11.4.6 Find C(9,6) on Pascal's triangle.
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RESPONSE --> Row 9 go over 7 =84
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10:30:55 ** You need to go to the n=9 row, the r=6 position, which is the 10th row and the 7th number in the row. Looks like you went to the 6th position. Note that C(9,6) = 9! / ( 6! (6-3)! ) = 9*8*7 / (3*2*1) = 3 * 4 * 7 = 84 does agree with the number in the n = 9 row and the r = 6 position. Note also that since the first row is row 0 and the first element in every row is element 0, the n = 9 row is the 10th row, and the r = 6 position is the 7th number from the left. **
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RESPONSE --> I understand how to find the on the table
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10:32:47 Query 11.4.18 clueless check of four of nine possible classroomsHow many of the possible selections will fail to locate the classroom?
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RESPONSE --> 70
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10:34:08 Query 11.4.30 What sequence by totaling diagonals of Pascal's Triangle?
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RESPONSE --> 15, 21,28, 36, 45
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10:34:42 ** The numbers 1, 1, 2, 3, 5, 8, 13, 21, ... form what is called the Fibonacci Sequence, which seems to occur in all sorts of unexpected places. The sums of the diagonals are all Fibonacci numbers. **
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RESPONSE --> I understand that these are Fibonacci's numbers
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10:35:40 Query 11.4.42 (x+y)^8
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RESPONSE --> My book doesn't have a 42 for section 11.4
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10:36:29 **(x + y ) ^ 8 = x^8 + C(8,1) x^7 y + C(8,2) x^6 y^2 + C(8,3) x^5 y^3 + C(8,4) x^4 y^4 + C(8,5) x^3 y^5 + C(8,6) x^2 y^6 + C(8,7) x^7 y + y^8 = x^8 + 8 x^7 y + 28 x^6 y^2 + 56 x^5 y^3 + 70 x^4 y^4 + 56 x^3 y^5 + 28 x^2 y^6 + 8 x y^7 + y^8. **
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RESPONSE --> ok
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10:39:13 Query Add comments on any surprises or insights you experienced as a result of this assignment.
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RESPONSE --> I'm a little concerned that my book is different, because sometimes the numbers are off or I don't have the question at all. I also noticed that one of the sections listed to do is 12.6, but my book dosen't have this. I bought the book from the bookstore.
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