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course Mth 277
6/8 at 5pm
Question 1: 12 meters squaredConfidence:3
OK
Question 2: 6 meters squared
Confidence:3
OK
Question 3: 10 meters squared
These problems are so simple and easy I do not feel it is necessary to show step by step for the solutions.
Confidence:3
OK
Question 4: 1/2*base*height=.5*5*2=5 cm squared
Confidence:3
OK
Question 5: If the width is measured from left to right it makes sense to say the altitudes are 7 and 11 because those are the lengths of the two line segments and that is what the altitudes are.
I agree the figure appears to be sitting on the x axis with these altitudes because that is where the base actually sits. And the distance it runs along the x axis is 6 units so that is the graph width.
I would say the average graph altitude is 9 because that is the average calculated between 7 and 11 which are the two altitudes.
If I drew a rectangle with the same width and the same length that is the average graph altitude, it's area would be the same as this trapezoid.
Confidence:2 because it is a lot of information and a bit confusing when trying to decipher through it all.
OK
Question 6: The area of this graph trapezoid would be 22 cm squared.
The average altitude between the 3 and the 8 given would be 5.5 cm. And when we multiply this by 4 we get the 22.
Confidence:3
OK
Question 7: The radius of this circle would be 9*pi squared cm. It is easiest to leave the pi in that form instead of multiplying it out. The formula is pi*r^2
Confidence:3
OK
Question 8: The circumference of a circle who has a radius of 3 is 6 pi cm because the circumference is 2*pi*radius.
Confidence:3
OK
Question 9: The area of circle with a diameter of 12 is pi*r^2 and the r would be half the diameter which would be 6. so it would be 36 pi meters squared.
Confidence:3
OK
Question 10: If a circle has a circumference of 14 pi meters, then the area would be 49 pi meters squared. The C=2*pi*r which tells us that the radius is 7. Therefore, the area is pi*r^2 so that gives us 49 pi meters squared.
Confidence:3
OK
Question 11: If a circle has an area of 78 squared meters, then the radius of the circle has to be 4.98 meters because we just substitute the 78 in for the A in the equation of the area. We also solve the equation out for r since that is what we are looking for.
r=sqrt(A/pi)
r=sqrt(78/pi)=4.98 meters
Confidence: 3
OK
Question 12: We visualize the area of a rectangle by taking the number of units for the length and multiplying it by the number of units for the width. On a graph, this can often be visualized with blocks.
Confidence:3
OK
Question 13: We visualize the area of a right triangle by counting the number of units that go along the base and along the height. These are the two sides that form the right angle and then we multiply those units together and then half that number.
Confidence:3
OK
Question 14: We calculate the area of a parallelogram by multiplying the number of units that make up the base times the number of units that make up the altitude which is the line segment that is perpendicular to the base.
Confidence:3
OK
Question 15: The area of a trapezoid is calculated by taking the average altitude which we expanded and learned more about in a previous problem and multiplying it by the width.
Confidence:3
OK
Question 16: We calculate the area of a circle just like we have a lot in this review. We take the radius and square it and multiply it by pi.
Confidence:3
OK
Question 17: We calculate the circumference of the circle by take 2*pi*radius.
Confidence:3
OK
Question 18: Much of this assignment was very simple and easy for me. It was all review. I have memorized or always been given the formulas for this information and I have had a lot of practice. It is very simple math to me.
Confidence:3
OK
***I realize that I need to type into the forms and not erase the questions.I did not get your comments back until the end of this document. I answered all of these with complete sentences and with a topic sentence that would allow me to understand the question that was asked as well. I will do this in future documents. I apologize. "
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Many of your document have contained good statements and are relatively self-contained.
As long as you have what you think you need on your access page, it's OK.
In the future I'm sure you will follow the prescribed format. No need to apologize.
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