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PHY 201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Seed Questions 1_07.2
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You should enter your answers using the text editor or word processor. You will then copy-and-paste it into the box below, and submit.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
Given variables: ds = 10 m, v0 = 0, a = 9.8 m/s^2, t = 8 s & 5 s, slope = .05 & .10
a = g * slope
a = 9.8 m/s^2 * 0.05
a = 0.49 m/s^2
a = g * slope
a = 9.8 m/s^2 * 0.10
a = 0.98 m/s^2
(0.49 m/s^2 + 0.98 m/s^2) / 2
1.47 m/s^2 / 2
0.735 m/s^2
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@& The first automobile accelerates from rest through 10 meters in 8 seconds. You can calculate its acceleration.
The slope .05 is not relevant to the calculation of the acceleration on either the first or the second of these intervals.
You do then need to slopes to answer the question about that average rate of change.*@
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@& See my note. You don't appear to be interpreting the questions correctly.
Send me a revision. You can easily calculate those accelerations.
The question of the average rate then needs to be reasoned carefully.*@
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