cq_1_271

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PHY 201

Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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SEED Question 27.1

A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.

• What is the weight of the ball?

answer/question/discussion: ->->->->->->->->->->->-> : Given: m = 400 g or 0.4 kg, F (t) = 2.5 N

This volume of water, at 1 g per cm^3, will have a mass of 400 grams and therefore a weight of 0.4 k.

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• What is the buoyant force on the ball?

answer/question/discussion: ->->->->->->->->->->->-> :

F (b) = m * g

F(b) = 0.4 kg * 2.5 N

@& Your calculation here asserts that force = mass * force. The units of force are N, while the units of mass * force would be kg * N.

There is no situation in which you would multiply mass by force. You would multiply mass * acceleration to get net force, but you would never multiply mass by force.*@

F (b) = 1.0 N

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• What therefore must be its volume?

answer/question/discussion: ->->->->->->->->->->->-> :

If the volume of water, at 1 g per cm^3, will have a mass of 400 grams, the volume must be 400 cm^3.

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• What is its density?

answer/question/discussion: ->->->->->->->->->->->-> :

D = m / v

D = 400 g / 400 cm^3

D = 1 g / cm^3

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20 mins

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@& Be sure to see my note.*@

&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.

Then please compare your old and new solutions with the expanded discussion at the link

Solution

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