cq_1_061

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Phy 201

Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_06.1_labelMessages **

For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.

A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.

answer/question/discussion: ->->->->->->->->->->->-> :

v0=10cm/s, vf=20cm/s, 'ds= 45cm

vAve= (vf+v0)/2= (20cm/s+10cm/s)/2= 15cm/s

'dv= 20cm/s-10cm/s=10cm/s

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A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.

answer/question/discussion: ->->->->->->->->->->->-> :

a=10cm/s^2, 'dt=3 sec, vf=50cm/s

'dv=a*'ds=3s*10cm/s=30cm

'dv=vf-v0

30=50cm/s-v0

v0=20cm/s

vAve=(50cm/s+20cm/s)/2=35cm/s

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A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.

answer/question/discussion: ->->->->->->->->->->->-> :

'ds=30cm, v0=0cm/s, a=20cm/s^2

vf^2=(0cm/s)2+2(20cm/s^2)(30cm)

vf^2=1200cm^2/s^2

sqrt(vf^2)=sqrt(1200cm^2/s^2)

vf=35cm/sec

'dv= 35cm/s-0cm/sec=35cm/s

vAve=(35cm/sec+0cm/sec)/2= 17.5cm/sec

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Then for each situation answer the following:

Is it possible from this information to directly determine vAve?

answer/question/discussion: ->->->->->->->->->->->-> :

Yes, shown above

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Is it possible to directly determine `dv?

answer/question/discussion: ->->->->->->->->->->->-> :

Yes, shown above

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&#Very good responses. Let me know if you have questions. &#