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Phy 201
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.1_labelMessages **
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve=2m/.64sec=3.1m/s
vAve=(vf+v0)/2
2*3.1m/s=vf+0m/s
6.1m/s-0m/s=vf
6.1m/s=vf
aAve=(vf-v0)/'dt= (3.1m/s-0)/.64s=9.5m/s^2
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Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve= 5m/1.05s= 4.8m/s
vAve=(vf+v0)/2
2*4.8m/s=vf+0
9.6m/s=vf
Yes with uncertainty it could range from 9.5m/s^2 to 9.6m/s^2
@&
9.6 m/s would be the final velocity. 9.6 m/s^2 would not be the acceleration. The acceleration would be closer to 9.1 m/s^2.
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Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
They are close to the gravity. Certain things could interfere with the acceleration as in air resistance.
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45 min
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