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course Phy 201
9/26 8
Determine the acceleration of an object whose velocity is initially 24 cm/s and which accelerates uniformly through a distance of 66 cm in 3.8 seconds.vAve=66cm/3.8s=17.4cm/s
vAve=(vf+v0)/2
17.4cm/s=(vf+24cm/s)/2
17.4cm/s*2=vf+24cm/s
34.8cm/s-24cm/s=vf
10.8cm/s=vf
aAve=(vf-v0)/'dt
aAve=(10.8cm/s-24cm/s)/3.8s
aAve=-.35cm/s^s"
&#Very good work. Let me know if you have questions. &#