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course Phy 201
10/3 2
An object is given an unknown initial velocity up a long ramp on which its acceleration is known to have magnitude 11 cm/s^2. .131 seconds later it passes a point 7.9 cm up the ramp from its initial position. What are its possible initial velocities, and what is a possible scenario for each?
What is the maximum distance the object travels up the ramp?
7.9cm=v0(.131s)+.5(-11cm/s^2)(.131s)^2
7.99=v0(.131s)
61cm/s=v0
7.9cm=v0(.131s)+.5(11cm/s^2)(.131s)^2
7.81cm=v0(.131s)
60cm/s=v0
a=(vf-v0)/'dt=(0cm/s-60cm/s)/-11cm/s=6.1s
vAve=('ds/'dt)=(v0+vf)/2*'dt=6.1s*(60+0)/2=183m"
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It is valid to use -11 cm/s^2 as your acceleration, but do note that you didn't use the right units.
You would not, however, use -11 cm/s^2 with an initial velocity that was obtained assuming an acceleration of + 11 cm/s^2.
Should be very easy to fix, but once more pay close attention to detail.
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