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Phy 201
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_24.2_labelMessages **
A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
initial:( 0.06 kg * .8 m/s) + (.02 kg * 0 m/s) = 0.048 kg*m/s,
Final:( 0.06 kg * .5 m/s) + (.02 kg * .7 m/s) = (0.03 kg*m/s) + (0.014 kg*m/s) = 0.044 kg*m/s
Final was greater
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What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
.03 kg*m/s .048 kg m/s
total momentum = .03 kg m/s + marble momentum = .048 kg m/s
.048 kg*m/s - .03 kg*m/s = .018 kg*m/s
.02 kg * v_marble= .018 kg m/s and
v_marble = .018 kg m/s / (.02 kg) = 0.9 m/s
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