#$&* course Phy 201 11/14 11 If your solution to stated problem does not match the given solution, you should self-critique per instructions at
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Given Solution: Since 1 radian of angle corresponds to the distance along the arc which is equal to the radius, if the radius of the circle is 40 meters then a 1 radian angle would correspond to a distance of 40 meters along the arc. An angle of 3 radians would correspond to a distance of 3 * 40 meters = 120 meters along the arc. Each radian corresponds to a distance of 40 meters along the arc. STUDENT COMMENT: ok, I answered '40 m for one radian and 120m for three' I thought there was some formula and it couldn't be this easy to figure out. INSTRUCTOR RESPONSE It really is this easy, and this is the most important thing you need to remember about radian measure. There are formulas relating arc distance to radian measure (and arc velocity to angular velocity, and acceleration along the arc to angular acceleration), and they are simple formulas, but they are difficult to keep straight. It's difficult to remember what symbol goes with what, and when you multiply by r and when you divide, and when there's a 2 pi involved and whether you divide by that or multiply. Of course you haven't seen the formulas yet and don't yet know what all that means, but that last paragraph should alert you to one simple fact: There's one simple idea at work here, you just used it, you understand it, and if you never lose track of it there are a whole lot of confusing formulas that will just come down to common sense. (You'll also want to keep in mind that the circumference of a circle is 2 pi r, but it's assumed that you know this.) &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q002. On a circle of radius 40 meters, how far would you have to walk to go all the way around the circle, and through how many radians of angle would you therefore travel? Through how many radians would you travel if you walked halfway around the circle? Through how many radians would you travel if you walked a quarter of the way around the circle? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 2 `pi * 40 meters = 80 `pi meters. 80 * 3.14 meters = 251 meters (approx). 1/2 ( 80 `pi meters) = 40 `pi meters. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: The circumference of a circle is the product of `pi and its diameter, or in terms of the radius r, which is half the diameter, C = 2 `pi r. The circumference of this circle is therefore 2 `pi * 40 meters = 80 `pi meters. This distance can be left in this form, which is exact, or if appropriate this distance can be approximated as 80 * 3.14 meters = 251 meters (approx). The exact distance 2 `pi * 40 meters is 2 `pi times the radius of the circle, so it corresponds to 2 `pi radians of arc. Half the arc of the circle would correspond to a distance of half the circumference, or to 1/2 ( 80 `pi meters) = 40 `pi meters. This is `pi times the radius so corresponds to `pi radians of angle. A quarter of an arc would correspond to half the preceding angle, or `pi/2 radians. STUDENT QUESTION A quarter of the arc would be pi/2 radians so, it would not be 40 pi/2 radians..I dont understand? INSTRUCTOR RESPONSE A quarter of the arc would be pi/2 radians, so the distance around the arc on this circle would be 40 pi/2 meters. Be careful not to confuse the distance along the arc, which is measured in meters and which you could actually walk, with the angle, which is measured in radians (if you were standing at the center you could turn through the angle, but you would do that without moving anywhere). You would have to go 80 pi meters to go around the whole circle, and this corresponds to an anglular displacement of 2 pi radians. You would only have to go 40 pi meters to get around half the circle, and you would have only half the angular displacement. The previous angular displacement was 2 pi radians, so halfway around would correspond to pi radians. To go a quarter of the way around you would travel 20 pi meters, and your angular displacement would be pi/2 radians. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q003. On a circle of radius 6 meters, what distance along the arc would correspond to 3 radians? What distance would correspond to `pi / 6 radians? What distance would correspond to 4 `pi / 3 radians? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 3 * 6 meters, or 18 meters. `pi / 6 * 6 meters = `pi meters. 4 `pi / 3 * 6 meters = 8 `pi meters confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: 3 radians along the arc would correspond to an arc distance of 3 times the radius, or 3 * 6 meters, or 18 meters. `pi / 6 radians would correspond to `pi / 6 times the radius, or `pi / 6 * 6 meters = `pi meters. 4 `pi / 3 radians would correspond to 4 `pi / 3 * 6 meters = 8 `pi meters. STUDENT COMMENT I'm still not really clear on how to simplify the given equations. INSTRUCTOR RESPONSE You got the correct expressions, you just didn't simplify them. It might be that you didn't recognize these as fractional expressions. You should write these fractions out. For example a / c * b means 'multiply by a then divide by c, then multiply the result by b'. So a / c * b means (a / c) * b. (a/c) can be written as a fraction, with a in the numerator and b in the denominator. b can also be written as a fraction, with b in the numerator and 1 in the denominator. So (a / c) * b means (a / c) * (b / 1). When two fractions are multiplied, their numerators are multiplied, and their denominators are multiplied. So (a/c) * (b/1) = (a * b) / (c * 1), which simplifies to a * b / c. The expression 4 pi / 3 * 6 means (4 pi / 3 ) * 6, which means (4 pi * 6) / 3 = (24 pi / 3). Since 24 / 3 = 8, the expression (24 pi / 3) reduces to 8 * pi. pi / 6 * 6 means (pi * 6) / 6, or 6 pi / 6. Since 6 / 6 = 1, the expression (6 pi / 6) reduces to 1 * pi, or just pi. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q004. If you were traveling around a circle of radius 50 meters, and if you traveled through 4 radians in 8 seconds, then how fast would you have to be moving? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 4 * 50 meters = 200 meters. 200 meters / (8 seconds) = 25 m/s confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: If you travel 4 radians along the arc you half traveled an arc distance of 4 times the radius, or 4 * 50 meters = 200 meters. If you traveled this distance in 8 seconds your average speed would be 200 meters / (8 seconds) = 25 m/s. COMMON STUDENT SOLUTION 50 meters * 4 = 200 meters/8 seconds= 25 m/s INSTRUCTOR COMMENT I can see how you've thought this through and your thinking is absolutely correct. However the first expression 50 meters * 4 is not equal to you last expression 25 m/s. However these expressions are connected by a chain of equal signs and should therefore be equal (this is called the 'transitive property of multiplication'). What you clearly mean is 50 m * 4 = 200 meters 200 m / (8 sec) = 50 m/s. Your train of thought it clear and correct. However equal signs should be used only to indicate equality. Confusion can easily result when equal signs are used to indicate train of thought. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q005. Traveling at 3 radians / second around a circle of radius 20 meters, how fast would you have to be moving? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 3 * 20 meters = 60 meters confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: 3 radians along the arc is a distance of 3 times the radius, or 3 * 20 meters = 60 meters. Moving at 3 radians/second, then, the speed along the arc must be 60 meters /sec. NEARLY CORRECT STUDENT SOLUTION 20 meters * 3 = 60 meters/sec INSTRUCTOR COMMENT Your intent is clear and correct. However the units of your calculation don't work out: 20 meters * 3 = 60 meters, not 60 meters / second. What you know is that every second the object moves through an angular displacement of 3 radians, which on a circle of 20 m radius implies an arc distance of 60 meters. We conclude that the speed along the arc is 60 m/s. The problem with the notation can be fixed up as follows: 1 radian of angle corresponds to a distance equal to the radius. The units of this calculation could be expressed as 1 meter of radius * 1 radian of angle = 1 meter of arc distance. We can abbreviate this as 1 meter * 1 radian = 1 meter, understanding that the meter on the left corresponds to a meter of radius, while the meter on the right corresponds to 1 meter of arc distance. Then our calculation becomes 20 meters * 3 radians / second = (20 meters * 3 radians) / second = 60 meters / second, where we understand that the 20 meters on the left stands for radius and the 60 meters on the right stands for arc distance. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q006. If you know how many radians an object travels along the arc of a circle, and if you know the radius of the circle, how do you find the distance traveled along the arc? Explain the entire reasoning process. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: The distance along the arc is 1 radius for every radian. Therefore we times the radians by the radius of the circle to get the arc confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: The distance traveled along the arc of circle is 1 radius for every radian. Therefore we multiply the number of radians by the radius of the circle to get the arc distance. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q007. If you know the distance an object travels along the arc of a circle, and if you know the radius of the circle, how do you find the corresponding number of radians? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: An arc is equal to the radius corresponds to a radian and divide the arc by the radius you get radians. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: An arc distance which is equal to the radius corresponds to a radian. Therefore if we divide the arc distance by the radius we obtain the number of radians. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q008. If you know the time required for an object to travel a given number of radians along the arc of a circle of known radius, then how do you find the average speed of the object? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: Number of radians multiply the number of radians by the radius to get the distance along the arc and divide distance along the arc by the time gives the average speed of the object. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: If you know the number of radians you can multiply the number of radians by the radius to get the distance traveled along the arc. Dividing this distance traveled along the arc by the time required gives the average speed of the object traveling along the arc. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q009. If you know the speed of an object along the arc of a circle and you know the radius of the circle, how do you find the angular speed of the object in radians/second? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: The speed of the object is the distance it travels along the arc per unit of time. The angular velocity is the number of radians through which the object travels per unit of time. The distance traveled and the number radians are related by the fact that the distance is equal to the number of radians multiplied by the radius. So if the distance traveled in a unit of time is divided by the radius, we get the number of radians in a unit of time. So the angular speed is found by dividing the speed along the arc by the radius. STUDENT ANSWER: change in radians (distance) /time INSTRUCTOR RESPONSE Right idea; one small correction: the denominator should be change in clock time, or time interval, not just 'time' The angular speed on an interval is the angular distance during that interval (which you clearly indicated as 'change in radians (distance)', divided by change in clock time or time interval. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): ------------------------------------------------ Self-critique rating: ********************************************* Question: `q010. We usually let `d`theta stand for the angular displacement in radians between two points on the arc of the circle. We usually let `omega stand for the angular velocity in radians / second. We let `ds stand for the distance traveled along the arc of a circle, and we let r stand for the radius of the circle. If we know the radius r and the arc distance `ds, what is the angular displacement `d`theta, in radians? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: `d`theta = `ds / r. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: Since an angular displacement of 1 radian corresponds to an arc distance equal to the radius, the angular displacement `theta in radians is equal to the number of radii in the arc distance `ds. This quantity is easily found by dividing the arc distance by the radius. Thus `d`theta = `ds / r. STUDENT QUESTION: Omega (velocity in radians/second)/ radius = angular speed= angular displacement/time '(velocity in radians / second) / radius' implies that you divide the number of radians by the radius to get the angular displacement, when in fact you would divide the angular displacement by the radius to get the number of radians. `d`theta = `ds / r I'm getting confused by this now. INSTRUCTOR RESPONSE The angle (number of radians) corresponding to an arc distance is found by dividing arc distance by radius. As you say: `dTheta = `ds / r. That is, angular displacement is arc displacement divided by radius. So if you know the arc displacement during a certain time interval, the angular displacement during that same interval is found by dividing the arc displacement by the radius. Thus angular displacement per unit of time is equal to arc displacement per unit of time, divided by radius: omega = v / r. Rule of thumb: If it's along the arc you divide by the radius to get the angular quantity; if it involves angle you multiply by radius to get the arc quantity. This follows directly from the reasoning you used in the very first problem of this document. Applying the rule of thumb: v is along the arc, omega involves angle. We divide arc displacement by radius to get angle in radians. More specifically: v is velocity along the arc, so v / r involves (among other things) dividing an arc displacement by radius. The result is an angular displacement. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q011. If we know the radius r of a circle and the angular velocity `omega, how do we find the velocity v of the object as it moves around the arc of the circle? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: v = `omega * r. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: The angular velocity is the number of radians per second. The velocity is the distance traveled per second along the arc. Since an angular displacement of 1 radian corresponds to an arc distance equal to the radius, if we multiply the number of radians per second by the radius we get the distance traveled per second. Thus v = `omega * r. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q012. We can change an angle in degrees to radians, or vice versa, by recalling that a complete circle consists of 360 degrees or 2 `pi radians. A half-circle is 180 degrees or `pi radians, so 180 degrees = `pi radians. How many radians does it take to make 30 degrees, how many to make 45 degrees, and how many to make 60 degrees? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 30 degrees is 1/6 of 180 degrees and therefore corresponds to 1/6 * `pi radians, usually written as `pi/6 radians. 45 degrees is 1/4 of 180 degrees and therefore corresponds to 1/4 * `pi radians, or `pi/4 radians. 60 degrees is 1/3 of 180 degrees and therefore corresponds to 1/3 * `pi radians, or `pi/3 radians confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: 30 degrees is 1/6 of 180 degrees and therefore corresponds to 1/6 * `pi radians, usually written as `pi/6 radians. 45 degrees is 1/4 of 180 degrees and therefore corresponds to 1/4 * `pi radians, or `pi/4 radians. 60 degrees is 1/3 of 180 degrees and therefore corresponds to 1/3 * `pi radians, or `pi/3 radians. STUDENT QUESTION I mathematically solved for a numerical value of how many radians there were. For example, 30 deg is 1/6 of 180 deg, so it's pi / 6 radians. I got .78 radians, which I rounded to .8 radians. Based on the answer in the given solution, I should not have done this. Answers were left as ‘pi/6 radians, ‘pi/4 radians, and ‘pi/3 radians. Is the answer technically wrong solved the way that I did it??? Or does it need to be written the way it was in the given solution. INSTRUCTOR RESPONSE Only the multiple-of-pi results are exact. Anything else is a rounded approximation. For the special angles (angles which are multiples of pi/4 and pi/6), we can find their exact sines and cosines. So we use the expressions for the exact angles. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q013. Since 180 deg = `pi rad, we can convert an angle from degrees to radians or vice versa if we multiply the angle by either `pi rad / (180 deg) or by 180 deg / (`pi rad). Use this idea to formally convert 30 deg, 45 deg and 60 deg to radians. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 30 deg * ( `pi rad / 180 deg) = (30 deg / (180 deg) ) * `pi rad = 1/6 * `pi rad = pi/6 rad. 45 deg * (`pi rad / 180 deg) = ( 45 deg / ( 180 deg) ) * `pi rad = 1/4 * `pi rad = `pi/4 rad. 60 deg * (`pi rad / 180 deg) = ( 60 deg / ( 180 deg) ) * `pi rad = 1/3 * `pi rad = `pi/3 rad confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: To convert 30 degrees to radians, we multiply by the rad / deg conversion factor, obtaining 30 deg * ( `pi rad / 180 deg) = (30 deg / (180 deg) ) * `pi rad = 1/6 * `pi rad = pi/6 rad. To convert 45 degrees to radians we use the same strategy: 45 deg * (`pi rad / 180 deg) = ( 45 deg / ( 180 deg) ) * `pi rad = 1/4 * `pi rad = `pi/4 rad. To convert 60 degrees: 60 deg * (`pi rad / 180 deg) = ( 60 deg / ( 180 deg) ) * `pi rad = 1/3 * `pi rad = `pi/3 rad. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q014. Convert 50 deg and 78 deg to radians. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 50 deg * (`pi rad / 180 deg) = ( 50 deg / ( 180 deg) ) * `pi rad = 5/18 * `pi rad = (5 `pi/ 18) rad. 78 deg * (`pi rad / 180 deg) = ( 78 deg / ( 180 deg) ) * `pi rad = 78/180 * `pi rad = (13 `pi/ 30) rad. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: 50 deg * (`pi rad / 180 deg) = ( 50 deg / ( 180 deg) ) * `pi rad = 5/18 * `pi rad = (5 `pi/ 18) rad. 78 deg * (`pi rad / 180 deg) = ( 78 deg / ( 180 deg) ) * `pi rad = 78/180 * `pi rad = (13 `pi/ 30) rad. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q015. Convert (14 `pi / 9) rad to degrees. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: (14 `pi / 9) rad * ( 180 deg / (`pi rad)) = ( 14 `pi / 9 ) * (180 / `pi ) deg = ( 14 * 180 / 9) * (`pi / `pi) deg = 14 * 20 deg = 280 deg. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: Since the angle is given radians, we need to multiply by deg / rad to get the angle in degrees. (14 `pi / 9) rad * ( 180 deg / (`pi rad)) = ( 14 `pi / 9 ) * (180 / `pi ) deg = ( 14 * 180 / 9) * (`pi / `pi) deg = 14 * 20 deg = 280 deg. STUDENT QUESTION The only problem I ran into when solving is that I was unable to mathematically remove radians from the equation that I set up. I know that they are not supposed to be part of the answer to the problem, but I’m not sure how to get rid of it from the answer. INSTRUCTOR RESPONSE As in your calculation 14 pi/9 rad * 180 degrees / (pi rad), the units come down to rad * deg / rad. The radians divide out, being present in both numerator and denominator, leaving degrees. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):ok ------------------------------------------------ Self-critique rating:3 ********************************************* Question: `q016. What would be the length on a circle of radius 40 cm of an arc which corresponds to (or more correctly, which 'subtends') an angle of pi/12 radians? What about an arc that subtends an angle of 80 degrees? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your Solution: confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ ********************************************* Question: `q017. What angle would be subtended by an arc of length 25 cm on a circle of radius 12 cm? What would be the angular velocity of a point moving around a circle of radius 12 cm with a speed of 25 cm/sec? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your Solution: confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ " Self-critique (if necessary): ------------------------------------------------ Self-critique rating: ********************************************* Question: `q016. What would be the length on a circle of radius 40 cm of an arc which corresponds to (or more correctly, which 'subtends') an angle of pi/12 radians? What about an arc that subtends an angle of 80 degrees? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your Solution: confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ ********************************************* Question: `q017. What angle would be subtended by an arc of length 25 cm on a circle of radius 12 cm? What would be the angular velocity of a point moving around a circle of radius 12 cm with a speed of 25 cm/sec? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your Solution: confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ " Self-critique (if necessary): ------------------------------------------------ Self-critique rating: #*&! ********************************************* Question: `q016. What would be the length on a circle of radius 40 cm of an arc which corresponds to (or more correctly, which 'subtends') an angle of pi/12 radians? What about an arc that subtends an angle of 80 degrees? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your Solution: confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ ********************************************* Question: `q017. What angle would be subtended by an arc of length 25 cm on a circle of radius 12 cm? What would be the angular velocity of a point moving around a circle of radius 12 cm with a speed of 25 cm/sec? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your Solution: confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ " Self-critique (if necessary): ------------------------------------------------ Self-critique rating: #*&!#*&!