#$&* course MTH 279 Query 13 Differential Equations*********************************************
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): OK ------------------------------------------------ Self-critique rating: OK ********************************************* Question: Find the largest interval on which the equation t y '' + sin(2 t) / (t^2 - 9) y ' + 2 y = 0 has a solution, with the initial conditions y(1) = 0, y ' (1) = 1. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: y’’ + sin(2t)/(9(t^2-9)) y’ + 2y/t = 0 p(t) = sin(2t)/(9(t^2-9)), continuous for all t ≠ 0,±3 (-∞,-3)(-3,0)(0,3)(3,∞); q(t) = 2/t, continuous for all t≠0 (-∞,0)(0,∞); g(t) = 0, continuous for all real values of t (-∞,∞); Initial conditions are imposed at t = 1, so the largest interval on which the equation has a solution is 0 < t < 3, or (0,3). confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): OK ------------------------------------------------ Self-critique rating: OK