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PHY 231
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
7 cm/sec
Found by (10 cm/s + 4 cm/s)/2
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• Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
This question can be nothing more than a guess with the given information because it does not state uniform acceleration. It is possible that the ball rolled a good distance before almost stopping and then began down a short hill where it was measured at 10 cm/s. There is simply no way to know; yet, 7 cm/s is the best GUESS we can provide.
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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
vAve = Change in position / change in time.
7 cm/s = Change in position / 3 s
Change in position = 21 cm
(Also a guess merely because the 7 cm/s we plugged in was a guess)
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• At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
aBar = (10 cm/s - 4 cm/s) / 3 s
aBar = 2 cm/s^2
This would be the average rate velocity changed with respect to clock time during the interval.
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&#Your work looks very good. Let me know if you have any questions. &#