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PHY 231
Your 'cq_1_09.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds.
• What are its average velocity, final velocity and acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
v_ave = 20 cm / 2 s
= 10 cm/s
10 cm/s = (vf + v0)/2
vf= 20 cm/s
a = (vf-v0) / dt
= 20 cm/s / 2 s
= 10 cm/s/s
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• If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve = 20 cm/2.06
= 9.71
9.71 = (vf+v0)/2
vf = 19.42 cm/s
a= (vf-v0)/2.06
=9.43 cm/s/s
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• What is the percent error in each?
answer/question/discussion: ->->->->->->->->->->->-> :
Final Velocity
.58 cm/s / 19.42 cm/s
.0298 or 2.98%
Acceleration
.57 cm/s/s / 9.43 cm/s/s
.0604 or 6.04%
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• If the percent error is the same for both velocity and acceleration, explain why this must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
NA
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• If the percent errors are different explain why it must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
Because Velocity has a relationship between position and time; whereas, acceleration has a relationship between velocity (where the error is already intergrated) with time again, which means acceleration has an indirect AND direct relationship with time make the error percent greater.
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15 min
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10/16 8:40
Very good responses. Let me know if you have questions.