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PHY 231
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
(.06kg * .8m/s) + (.02kg * 0m/s) = (.06kg * .5m/s) + (.02kg *.7m/s)
.048kg(m/s) = .044kg(m/s)
They are not exactly the same.
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• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
.06kg*.5m/s + .02kg*x
x = .9 m/s
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This looks very good. Let me know if you have any questions.