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PHY 231
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
F1 = 5kg * -9.8 m/s^2 = -49 N
F2 = 6 kg * 9.8 m/s^2 = 58.8 N (positive direction)
Fnet = 58.8N - 49N = 9.8 N
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
a = dv/dt
a = (vf - - 1.8m/s^2)/1s
a = 0.89m/s^2
0.89m/s^2 = vf + 1.8 m/s^2
vf = -0.91m/s
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
Opposite - Slows
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5 or so min
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&#Your work looks very good. Let me know if you have any questions. &#