course Mth 151 February 11 around 9:00
q1.2.36: I see that I must use division to find the remainders of the numbers in the sequence. By dividing the sequence numbers the new sequence of remainders would be 1,0,0,1,0,0. *2 on confidence scale q1.2.6: I would get: 2,57,220,575,1230,2317 55,163,355,655,1087 108,192,300,432 84,108,132 24,24 Finally we get the numbers by adding together: 132+24=156 432+156=588 1087+588=1675 2137+1675=3992 and so the next number would be 3992 *2 on confidence scale q001: The next equation in the sequence would be 4^2+4=5^2-5 because that would result us in getting 20=20 *2 on the confidence scale q1.2.30: You could also use other ways of predicting the next elements because of the n. *1 on confidence scale q1.2.48: I would put 12 as n and work out the formula given. Twelve divided by 2=6X12-4 to equal 6X68 to get 408. *2 on confidence scale