Assignment 38

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course Mth 158

7/24/12 at 10:59

If your solution to stated problem does not match the given solution, you should self-critique per instructions at http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.Your solution, attempt at solution:

If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

038. * 38

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Question: * 6.5.24 / 6.5.18 / 7th edition 5.5.18. Exact value of log{base 3}{(8) * log{base 8}(9).

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Your solution: You are looking for the power to raise 3 to 9, which is 2. This gives us log(base 3)(8)*log(base 8)(9) = 2.

confidence rating #$&*: 3

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Given Solution:

* * log{base 3}(8) * log{base 8}(9) = log 8 / log 3 * log 9 / log 8 = log 9 / log 3 = log{base 3}(9).

log{base 3}(9) is the power to which 3 must be raised to get 9, and is therefore equal to 2.

Thus log{base 3}(8) * log{base 8}(9) = 2.

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Question: * 6.5.30 / 6.5.24 / 7th edition 5.5.24. ln(2) = a, ln(3) = b. What is ln(2/3) in terms of a and b?

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Your solution: You have ln(2/3) = ln(2) - ln (3) which is a - b.

confidence rating #$&*: 3

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Given Solution:

* * ln(2/3) = ln(2) - ln(3) = a - b.

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Question: * 6.5.32 / 6.5.26 / 7th edition 5.5.26. ln(0.5) in terms of a and b.

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Your solution: We have ln(.5) = ln(1/2) = ln(1) -ln (2) = 0 - a = -a.

confidence rating #$&*: 3

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Given Solution:

* * Since ln(2) = a, and since ln(1) = 0, we have

ln(.5) = ln(1/2) = ln(1) - ln(2) = 0 - a = -a.

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Question: * Extra problem / 6.5.52 / 7th edition 5.5.52. log{base 3}(u^2) - log{base 3}(v) as a single log.

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Your solution: You have log(base 3)(u^2) - log(base 3) (v) = log(base 3(u^2)/v).

confidence rating #$&*: 3

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Given Solution:

* * log{base 3}(u^2) - log{base 3}(v) = log{base 3}(u^2 / v).

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Question: * Extra Problem / 6.5.58 / 7th edition 5.5.68. Using a calculator express log{base1 / 2}(15)

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Your solution: You have log(base ½)(15) = log(15)/log(1/2) = -3.906890596.

confidence rating #$&*: 3

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Given Solution:

* * We get log{base 1/2}(15) = log(15) / log(1/2) = 1.176091259 / )-0.3010299956) = -3.906890595.

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Question: * 6.5.88 / 6.5.82 / 7th edition 5.5.80. Express y as a function of x if ln y = ln(x + C).

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Your solution: You have (x+c) =e^y.

confidence rating #$&*: 2

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Given Solution:

* * a = ln(b) means e^a = b, so y = ln(x+c) is translated to exponential form as

(x+c) = e^y.

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#*&!

Assignment 38

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