\labrynth_2\levl1_00\levl2_64\file3_905.htm
http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_0
0\levl2_64\file3_905.htm
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course Phy 121
A ball falls freely from rest at a height of 2 meters. Observations
indicate that the ball reaches the ground in .64 seconds. •Based on
this information what is its acceleration?
answer/question/discussion:
v0 = 0m/s
`ds = 2m
`dt = .64s
`ds/`dt = vAve = 2m/.64s = 3.125m/s
Vf = 6.25m/s
Vf^2 = v0^2 +2a`ds
A = (vf^2 – v0^2) / 2`ds
A = (6.25m/s)^2 / 2(2m)
A = 39m^2/s^2 / 4m
A = 9.75m/s/s
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• Is this consistent with an observation which concludes that a
ball dropped from a height of 5 meters reaches the ground in 1.05
seconds?
answer/question/discussion:
????not sure how to do this one?
@&
You are given `ds and `dt for the vertical motion, and you know that v0 = 0. So this question is answered in a manner identical to the preceding.
*@
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• Are these observations consistent with the accepted value of
the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion:
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Self-critique (if necessary):
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Self-critique rating:
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