course MTH271

Monday, July 12th 2010 8:59 AM

Quiz 2

The depth of water in a certain uniform cylinder is given by the depth vs. clock time function y = .025 t2 + -1.4 t + 86.

What is the average rate at which depth changes between clock times t = 7.6 and t = 15.2?

• What is the clock time halfway between t = 7.6 and t = 15.2, and what is the rate of depth change at this instant?

• What function represents the rate r of depth change at clock time t?

• What is the value of this function at the clock time halfway between t = 7.6 and t = 15.2?

If the rate of depth change is given by dy/dt = .278 t + -1.9 then how much depth change will there be between clock times t = 7.6 and t = 15.2?

• Give the function that represents the depth.

• Give the specific function corresponding to depth 110 at clock time t = 0.

The average depth change from 7.6 to 15.2 is losing 6.308 change from 76.804 to 70.496.

The clock time between 7.6 and 15.2 is 11.4, and when 11.4 is plugged into the function you get 73.289.

The value of the function halfway between 7.6 and 15.2 at 11.4 is 73.289.

The depth change between 7.6 and 15.2 for the second function is gaining 2.1128 in depth changing from .2128 and 2.3256.

Depth equals .278 t + (-1.9).

The function 110 = .278 (0) + (-1.9) corresponds to the depth at 110 at a clock time at 0 I believe.