#$&*
Phy 121
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.2_labelMessages **
The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph
consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
'dt2+'dt1=13+5=18
18/2=9
9 sec is midpoint clock time
#$&*
What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
v2+v1=16+40=56
56/2=28
28 cm/s is midpoint velocity
#$&*
How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
'ds= vave* 'dt
'ds=28*8=224cm
#$&*
By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
'dt= 'dt2-'dt1 =13-5=8 seconds
#$&*
By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
'vave= vave2-vave1= 40-16= 24 cm/s
#$&*
What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
aveage rate of change of velocity= 'vave/'dt
=(24cm/s)/(8 sec)
=3 cm/s^2
#$&*
What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
rise = 'vave
=24 cm/s
#$&*
What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
run= 'dt
=8sec
#$&*
What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
slope = rise/ run = aveage rate of change of velocity
slope= 24
=3 cm/s^2
#$&*
What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
the motion of the object is increasing at a constant rate.
#$&*
What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
aveage rate of change of velocity= 'vave/'dt
=(24cm/s)/(8 sec)
=3 cm/s^2
#$&*
*#&!*#&!
@&
Your units were pretty good here; you might have missed the final units on one question but got them on most.
*@