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Phy 121
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_03.1_labelMessages.txt **
The problem:
A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
vAve='ds/'dt
vAve=30/5
=6 cm/s
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If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> n/discussion (start in the next line):
Since average velocity average of inital and final velocity, the intial velocity was 0 therefore the average is based off the final velocity divided
by 2. Meaning the average velocity times 2 gives final velocity in this case because intial was 0.
v_f= vAve*2
v_f= 6*2= 12 cm/s
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By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
velocity changed by 12 cm/s
12-0= 12 cm/s
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At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
average rate of change of velocity= 'vave/'dt
=(12cm/s)/(5 sec)
=2.4 cm/s^2
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What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
from left to right, starting at a time and point 0 this would be a increasing line at a constant increasing rate
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&#Very good responses. Let me know if you have questions. &#