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Phy 121
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.1_labelMessages **
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
v0=0
'ds=2m
'dt=.64
`ds = .5 a `dt^2
a='ds/(.5*'dt^2)
a=2m/(.5*(.64s)^2)
a=2m/.2048s^2
a=9.765m/s^2
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Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
a=5m/(.5*(1.05s)^2)
a=5m/.55125s^2
a=9.0703m/s^2
Therefore the ball dropped at 2 meters is traveling at a higher acceleration.
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Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
The 2 meter observation is consistent with the acceleration of gravity. The 5 meter observation is moving slower than acceleration of gravity.
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&#Very good work. Let me know if you have questions. &#