#$&*
Phy 121
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.2_labelMessages **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
'ds=10m
'dt=8s
slope=.05
a='ds/(.5*'dt^2)
a=10m/(.5*(8s)^2)
a=10m/32s^2
a=.3125m/s^2
'ds=10m
'dt=5s
slope=.10
a='ds/(.5*'dt^2)
a=10m/(.5*(5s)^2)
a=10m/25s^2
@&
You have an arithmetic error here; you lost track of that .5 in the denominator.
The correct result will be .8 m/s^2.
*@
a=.400m/s^2
.400m/s^2-.3125m/s^2=.0875m/s^2
Therefore acceleration is changing .0875m/s^2 with respect to the slope of the incline.
@&
This would be the change in the acceleration, not the rate of change of acceleration with respect to ramp slope. The requested rate also considers the change in ramp slope.
*@
#$&*
** **
10 min
** **
@&
&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes. &#
*@