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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
F=m a
F=12kg*3m/s^2
F=36N
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What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
a=Fnet/m
a=20N/4kg
a=5m/s^2
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If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do
you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
a=Fnet/m
a=20N/10kg
a=2m/s^2
There is a opposing force because it is moving at 1.5m/s^2 when it should be moving at 2m/s^2.
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Important distinction with terminology: It's accelerating at 1.5 m/s^2, not moving at 1.5 m/s^2. Its speed and velocity are continuously changing.
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What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Since the acceleration is 1.5m/s^2 and the mass has not changed:
Fnet=1.5m/s^2*10kg= 15N
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&#This looks good. See my notes. Let me know if you have any questions. &#