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Phy 121
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
F=sqrt((2N)^2 + (3N)^2) = 3.6N
angle measured= arctan(3N/2N)= 56.31degree
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What are the components of the equilibrant force?
x=-2N
y=-3N
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What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
angle=arctan(-3N/-2N)=56.31degree
since x is negative add 180degre
180degree+56degree=236degree
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Your work looks very good. Let me know if you have any questions.