course PHY 231 I am aware that this is being submitted far later than expected, but I am trying to catch up with all of my work. 骶͌Ά£ãîú²€â÷éæ†ÙrzvÒcåÖ¡assignment #000
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23:23:17 The Query program normally asks you questions about assigned problems and class notes, in question-answer-self-critique format. Since Assignments 0 and 1 consist mostly of lab-related activities, most of the questions on these queries will be related to your labs and will be in open-ended in form, without given solutions, and will not require self-critique. The purpose of this Query is to gauge your understanding of some basic ideas about motion and timing, and some procedures to be used throughout the course in analyzing our observations. Answer these questions to the best of your ability. If you encounter difficulties, the instructor's response to this first Query will be designed to help you clarify anything you don't understand. {}{}Respond by stating the purpose of this first Query, as you currently understand it.
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RESPONSE --> The Query is meant to test my understanding of what is in the assignment.
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23:24:44 If, as in the object-down-an-incline experiment, you know the distance an object rolls down an incline and the time required, explain how you will use this information to find the object 's average speed on the incline.
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RESPONSE --> Average speed is defined to be the total displacment divided by time. Divide the distance traveled by the time it took the object to roll down the incline and you will have an average speed recorded. confidence assessment: 3
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23:27:08 If an object travels 40 centimeters down an incline in 5 seconds then what is its average velocity on the incline? Explain how your answer is connected to your experience.
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RESPONSE --> The average velocity is 8cm/sec. Velocity is defined as distance / time. 40 cm / 5 sec = 8 cm/sec.
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23:32:34 If the same object requires 3 second to reach the halfway point, what is its average velocity on the first half of the incline and what is its average velocity on the second half?
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RESPONSE --> The same equation is used as I did last time. V = d/t. The distance is half as much as in the last problem because it reaches the halfway point. D = 20 cm. The time is given (t = 3 seconds). The average velocity for the first half is 20 cm / 3 seconds = 6.67 cm/sec. The second half takes 2 seconds because the object rolls down the incline for 5 seconds altogether as given in the last problem. the distance is 20 cm because this is the other half of the incline. So 20cm/2sec = 10 cm/sec. confidence assessment: 3
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23:33:29 Using the same type of setup you used for the first object-down-an-incline lab, if the computer timer indicates that on five trials the times of an object down an incline are 2.42 sec, 2.56 sec, 2.38 sec, 2.47 sec and 2.31 sec, then to what extent do you think the discrepancies could be explained by each of thefollowing: {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioningthe object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> All 5 options are possible discrepancies that could result in getting a different answer. confidence assessment: 3
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23:35:30 How much uncertainty do you think each of the following would actually contribute to the uncertainty in timing a number of trials for the object-down-an-incline lab? {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated bLine$(lineCount) =with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> All 5 options are possible and probable due to human discrepancy. The position is unlikely to be exactly as it was the last time. Air conditioning could change, in reality, everything listed probably had something to do with getting a different answer. Luckily, they were all relatively close. confidence assessment: 3
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23:37:37 What, if anything, could you do about the uncertainty due to each of the following? Address each specifically. {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actualdifferences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> A) Nothing can be done about the precision of the TIMER program. That is how it was created. B) A lot of practice can be done so that human triggering would be fairly consistent. C) Try to have the object roll down the same way so that it will cover the same distance at roughly the same time. D) Have a piece of tape or a landmark over the exact spot the object was put. E) Practice so there will be less uncertainty. confidence assessment: 3
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23:38:29 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> I do not think it would be exactly half due to uncertain complications. However, roughly doubling the length of the pendulum would result in half the frequency. confidence assessment: 2
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23:39:06 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> Point zero is meant to be an origin. It is meant to be a starting point for the graph. confidence assessment: 1
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23:39:42 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> Crossing the vertical axis would be with the direction of the pendulum. confidence assessment: 1
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23:40:29 On a graph of frequency vs. pendulum length, what would it mean for the graph to intersect the horizontal axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the horizontal axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> Crossing the horizontal axis again would mean that the distance is going to a positive or negative value. confidence assessment: 1
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23:41:57 If a ball rolls down between two points with an average velocity of 6 cm / sec, and if it takes 5 sec between the points, then how far apart are the points?
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RESPONSE --> d = 30 cm. d = velocity x time. d = 6 cm/sec x 5 sec = 30 cm. confidence assessment: 3
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23:42:08 On the average the ball moves 6 centimeters every second, so in 5 seconds it will move 30 cm. {}{}The formal calculation goes like this: {}{}We know that vAve = `ds / `dt, where vAve is ave velocity, `ds is displacement and `dt is the time interval. {}It follows by algebraic rearrangement that `ds = vAve * `dt.{}We are told that vAve = 6 cm / sec and `dt = 5 sec. It therefore follows that{}{}`ds = 6 cm / sec * 5 sec = 30 (cm / sec) * sec = 30 cm.{}{}The details of the algebraic rearrangement are asfollows:{}{}vAve = `ds / `dt. We multiply both sides of the equation by `dt:{}vAve * `dt = `ds / `dt * `dt. We simplify to obtain{}vAve * `dt = `ds, which we then write as{}`ds = vAve *`dt.{}{}Be sure to address anything you do not fully understand in your self-critique.
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RESPONSE --> ok self critique assessment: 3
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23:43:12 You were asked to read the text and some of the problems at the end of the section. Tell me about something in the text you understood up to a point but didn't understand fully. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I need to reread the dot products of vectors. Product vectors were confusing. I do not have a set question currently. I believe I simply need to reread the last sections in Chapter 1. confidence assessment: 2
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23:43:56 Tell me about something in the problems you understand up to a point but don't fully understand. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> Adding vectors just needs repetitive work but I think I am getting the hang of it. confidence assessment: 2
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